Python - 四舍五入到最接近的十
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Python - round up to the nearest ten
提问by raspberrysupreme
If I get the number 46 and I want to round up to the nearest ten. How do can I do this in python?
如果我得到数字 46 并且我想四舍五入到最接近的十。我怎么能在python中做到这一点？
46 goes to 50.
46 到 50。
采纳答案by Parker
You can use math.ceil()to round up, and then multiply by 10
您可以使用math.ceil()向上取整，然后乘以 10
import math
def roundup(x):
return int(math.ceil(x / 10.0)) * 10
To use just do
使用只是做
>>roundup(45)
50
回答by NPE
Here is one way to do it:
这是一种方法：
>>> n = 46
>>> (n + 9) // 10 * 10
50
回答by ch3ka
rounddoes take negative ndigitsparameter!
round确实采用负ndigits参数！
>>> round(46,-1)
50
may solve your case.
可能会解决您的情况。
回答by primussucks
This will round down correctly as well:
这也将正确舍入：
>>> n = 46
>>> rem = n % 10
>>> if rem < 5:
... n = int(n / 10) * 10
... else:
... n = int((n + 10) / 10) * 10
...
>>> 50
