Exec() 后的 PHP StdErr

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时间:2020-08-25 06:01:28  来源:igfitidea点击:

PHP StdErr after Exec()

phpexecstderr

提问by martin

In PHP I am executing a command with exec(), and it returns if successful an URL;

在 PHP 中,我使用 exec() 执行命令,如果成功则返回 URL;

$url = exec('report');

However, I want to check stderr, if something went wrong. How would I read the stream? I want to use php://stderr, but I am not sure how to use it.

但是,如果出现问题,我想检查 stderr。我将如何阅读流?我想使用 php://stderr,但我不确定如何使用它。

回答by Pascal MARTIN

If you want to execute a command, and get both stderrand stdout, not "merged", a solution would probably to use proc_open, which provides a great level of control over the command that's being executed -- including a way to pipe stdin/stdout/stderr.

如果你想执行一个命令,并同时获得stderrstdout,而不是“合并”,一个解决办法可能是使用proc_open,它提供了真实执行过的命令控制的一个伟大的水平-其中包括如何管stdin/ stdout/ stderr

And here is an example : let's consider we have this shell-script, in test.sh, which writes to both stderrand stdout:

这是一个例子:让我们考虑一下我们有这个 shell 脚本 in test.sh,它同时写入stderrstdout

#!/bin/bash

echo 'this is on stdout';
echo 'this is on stdout too';

echo 'this is on stderr' >&2;
echo 'this is on stderr too' >&2;

Now, let's code some PHP, in temp.php-- first, we initialize the i/o descriptors :

现在,让我们编写一些 PHP 代码,temp.php首先,我们初始化 i/o 描述符:

$descriptorspec = array(
   0 => array("pipe", "r"),  // stdin
   1 => array("pipe", "w"),  // stdout
   2 => array("pipe", "w"),  // stderr
);

And, then, execute the test.shcommand, using those descriptors, in the current directory, and saying the i/o should be from/to $pipes:

然后,test.sh在当前目录中使用这些描述符执行命令,并说 i/o 应该是 from/to $pipes

$process = proc_open('./test.sh', $descriptorspec, $pipes, dirname(__FILE__), null);

We can now read from the two output pipes :

我们现在可以从两个输出管道中读取:

$stdout = stream_get_contents($pipes[1]);
fclose($pipes[1]);

$stderr = stream_get_contents($pipes[2]);
fclose($pipes[2]);

And, if we output the content of those two variables :

而且,如果我们输出这两个变量的内容:

echo "stdout : \n";
var_dump($stdout);

echo "stderr :\n";
var_dump($stderr);

We get the following output when executing the temp.phpscript :

执行temp.php脚本时,我们得到以下输出:

$ php ./temp.php
stdout :
string(40) "this is on stdout
this is on stdout too
"
stderr :
string(40) "this is on stderr
this is on stderr too
"

回答by mpen

A little function that might be helpful:

一个可能有用的小功能:

function my_shell_exec($cmd, &$stdout=null, &$stderr=null) {
    $proc = proc_open($cmd,[
        1 => ['pipe','w'],
        2 => ['pipe','w'],
    ],$pipes);
    $stdout = stream_get_contents($pipes[1]);
    fclose($pipes[1]);
    $stderr = stream_get_contents($pipes[2]);
    fclose($pipes[2]);
    return proc_close($proc);
}

The exit code is returned and STDOUT and STDERR are reference params if you need them.

如果需要,将返回退出代码,并且 STDOUT 和 STDERR 是参考参数。

回答by Li-chih Wu

Another way to get unmerged stdout/stderr.

另一种获得未合并标准输出/标准错误的方法。

$pp_name = "/tmp/pp_test";
@unlink($pp_name);
posix_mkfifo($pp_name, 0777);
$pp = fopen($pp_name, "r+");
stream_set_blocking($pp, FALSE);
exec("wget -O - http://www.youtube.com 2>$pp_name", $r_stdout);
$r_stderr = stream_get_contents($pp);
var_dump($r_stderr);
fclose($pp);
unlink($pp_name);

If you want to ignore stdout and get only stderr, you can try this:

如果你想忽略 stdout 而只得到 stderr,你可以试试这个:

exec("wget -O - http://www.youtube.com 2>&1 >/dev/null", $r_stderr);

回答by hassan

The short way to do such a things with execis to return the exit code ( status of the command )

做这样的事情的简短方法exec是返回退出代码(命令的状态)

Note that I am trying to list a non-exists directory /non-dir/

请注意,我正在尝试列出一个不存在的目录 /non-dir/

exec('ls /non-dir/', $out, $retval);
var_dump($retval);

Output

输出

ls: cannot access '/non-dir/': No such file or directory
int(2)

ls: 无法访问 '/non-dir/': 没有这样的文件或目录
int(2)

Normally in unix-based system most of successful statuses codes is ( 0) so you can check your $retvalto know the status of the command.

通常在基于 unix 的系统中,大多数成功的状态代码是 ( 0),因此您可以检查$retval以了解命令的状态。

to dismiss the error from listing an invalid path ls: cannot access '/non-dir/': No such file or directoryyou can redirect your stderrto null

要消除列出无效路径的错误,ls: cannot access '/non-dir/': No such file or directory您可以将stderr重定向到 null

exec('ls /non-dir/ 2>/dev/null', $out, $retval);
var_dump($retval);

this will output :

这将输出:

int(2)

整数(2)

also if you need the error string to use it in any scenario you may redirect your stderrto the stdout.

此外,如果您需要错误字符串在任何情况下使用它,您可以将您的stderr重定向到stdout

exec('ls /non-dir/ 2>&1', $out, $retval);
print_r($out);
var_dump($retval);

this will output the following:

这将输出以下内容:

Array
(
    [0] => ls: cannot access '/non-dir/': No such file or directory
)
int(2)