bash 在单个程序中管理多个命令
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supervisord multiple commands in single program
提问by Verhogen
How do I make a program for supervisord execute a command like
我如何为 supervisord 制作一个程序执行类似的命令
make && run-my-app.sh
It seems to try to pass && run-my-app.shas arguments to make. I've tried different combinations of quotes around things, but I can't seem to get this syntax right.
它似乎试图&& run-my-app.sh作为参数传递给 make。我已经尝试了不同的引号组合，但我似乎无法正确理解这种语法。
回答by Peter Szeto
You can enclose it in quotes to make it evaluate as two separate commands instead of making it appear && run-my-app.sh as arguments to make.
您可以将其括在引号中，使其作为两个单独的命令进行评估，而不是将其显示为 && run-my-app.sh 作为要进行的参数。
command=/bin/bash -c "make && run-my-app.sh"
