bash 编译多个项目（使用 makefile），但停止第一个损坏的构建？
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Compile several projects (with makefile), but stop on first broken build?
提问by Kiril Kirov
I want to do somethinglike:
我想做类似的事情：
for i in *
do
if test -d $i
then
cd $i; make clean; make; cd -;
fi;
done
And this works fine, but I want "break" the for-loop in case of a broken build.
这工作正常，但我想for在构建损坏的情况下“中断” -loop。
Is there a way to do this? Maybe some kind of if-statement, that can check for success of make?
有没有办法做到这一点？也许某种 -if语句，可以检查make?
采纳答案by Blagovest Buyukliev
You can check whether the makehas exited successfully by examining its exit code via the $?variable, and then have a breakstatement:
您可以make通过$?变量检查其退出代码来检查 是否已成功退出，然后有一条break语句：
...
make
if [ $? -ne 0 ]; then
break
fi
回答by Eldar Abusalimov
You can use Make itself to achieve what you're looking for:
您可以使用 Make 本身来实现您想要的：
SUBDIRS := $(wildcard */.)
.PHONY : all $(SUBDIRS)
all : $(SUBDIRS)
$(SUBDIRS) :
$(MAKE) -C $@ clean all
Make will break execution in case when any of your target fails.
如果您的任何目标失败，Make 将中断执行。
UPD.
更新。
To support arbitrary targets:
支持任意目标：
SUBDIRS := $(wildcard */.) # e.g. "foo/. bar/."
TARGETS := all clean # whatever else, but must not contain '/'
# foo/.all bar/.all foo/.clean bar/.clean
SUBDIRS_TARGETS := \
$(foreach t,$(TARGETS),$(addsuffix $t,$(SUBDIRS)))
.PHONY : $(TARGETS) $(SUBDIRS_TARGETS)
# static pattern rule, expands into:
# all clean : % : foo/.% bar/.%
$(TARGETS) : % : $(addsuffix %,$(SUBDIRS))
@echo 'Done "$*" target'
# here, for foo/.all:
# $(@D) is foo
# $(@F) is .all, with leading period
# $(@F:.%=%) is just all
$(SUBDIRS_TARGETS) :
$(MAKE) -C $(@D) $(@F:.%=%)
