bash 以秒为单位获取 UTC 时间
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/24547655/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Get UTC time in seconds
提问by Romanzo Criminale
It looks like I can't manage to get the bash UTC date in second. I'm in Sydney so + 10hours UTC time
看起来我无法在第二秒内获得 bash UTC 日期。我在悉尼 + 10 小时 UTC 时间
date
Thu Jul 3 17:28:19 WST 2014
date -u
Thu Jul 3 07:28:20 UTC 2014
But when I tried to convert it, I'm getting the same result which is not UTC time
但是当我尝试转换它时，我得到了相同的结果，这不是 UTC 时间
date +%s
1404372514
date -u +%s
1404372515
What am I missing here?
我在这里缺少什么？
After getting an answer saying date +%swas returning UTC time, here are more details about the problem I'm facing now.
在得到答复说date +%s返回 UTC 时间后，这里是有关我现在面临的问题的更多详细信息。
I'm trying to compare a date written in a file with python. This date is written in seconds in UTC time. And the bash date +%sdoesn't give me the same one. Actually if I'm doing in python time.asctime(time.localtime(date_in_seconds_from_bash)), I get the current time of Sydney, not UTC. I don't understand.
我正在尝试将文件中写入的日期与 python 进行比较。此日期以 UTC 时间的秒数表示。bashdate +%s并没有给我同样的结果。实际上，如果我在 python 中做time.asctime(time.localtime(date_in_seconds_from_bash))，我会得到悉尼的当前时间，而不是 UTC。我不明白。
回答by JamesNoonan33
I believe +%sis seconds since epoch. It's timezone invariant.
我相信+%s是自纪元以来的几秒钟。它是时区不变的。
回答by Derek Boonstra
I bet this is what was intended as a result.
我敢打赌，这就是预期的结果。
$ date -u --date=@1404372514
Thu Jul 3 07:28:34 UTC 2014
回答by Keith Thompson
You say you're using:
你说你正在使用：
time.asctime(time.localtime(date_in_seconds_from_bash))
where date_in_seconds_from_bashis presumably the output of date +%s.
其中date_in_seconds_from_bash是推测的输出date +%s。
The time.localtimefunction, as the name implies, gives you local time.
time.localtime顾名思义，该函数为您提供本地时间。
If you want UTC, use time.gmtime()rather than time.localtime().
如果您想要 UTC，请使用time.gmtime()而不是time.localtime().
As JamesNoonan33's answersays, the output of date +%sis timezone invariant, so date +%sis exactly equivalent to date -u %s. It prints the number of seconds since the "epoch", which is 1970-01-01 00:00:00 UTC. The output you show in your question is entirely consistent with that:
正如JamesNoonan33 的回答所说， 的输出date +%s是时区不变的，因此date +%s完全等同于date -u %s. 它打印自“纪元”以来的秒数，即1970-01-01 00:00:00 UTC. 您在问题中显示的输出与此完全一致：
date -u
Thu Jul 3 07:28:20 UTC 2014
date +%s
1404372514 # 14 seconds after "date -u" command
date -u +%s
1404372515 # 15 seconds after "date -u" command
回答by Adam
One might consider adding this line to ~/.bash_profile(or similar) in order to can quickly get the current UTC both as current time and as seconds since the epoch.
人们可能会考虑将此行添加到~/.bash_profile（或类似的）中，以便可以快速获取当前 UTC 作为当前时间和自纪元以来的秒数。
alias utc='date -u && date -u +%s'
alias utc='date -u && date -u +%s'
