将 JSON 字符串内容解析为 PHP 数组
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Parse JSON string contents into PHP Array
提问by tony2
I am trying to parse a string in JSON, but not sure how to go about this. This is an example of the string I am trying to parse into a PHP array.
我正在尝试解析 JSON 中的字符串，但不知道如何处理。这是我试图解析为 PHP 数组的字符串示例。
$json = '{"id":1,"name":"foo","email":"[email protected]"}';
Is there some library that can take the id, name, and email and put it into an array?
是否有一些库可以将 id、name 和 email 放入数组中？
回答by MrCode
It can be done with json_decode(), be sure to set the second argument to truebecause you want an array rather than an object.
可以使用json_decode()，确保将第二个参数设置为 ，true因为您需要一个数组而不是一个对象。
$array = json_decode($json, true); // decode json
Outputs:
输出：
Array
(
[id] => 1
[name] => foo
[email] => [email protected]
)
回答by Musa
Try json_decode:
尝试json_decode：
$array = json_decode('{"id":1,"name":"foo","email":"[email protected]"}', true);
//$array['id'] == 1
//$array['name'] == "foo"
//$array['email'] == "[email protected]"
回答by Errol Fitzgerald
$obj=json_decode($json);
echo $obj->id; //prints 1
echo $obj->name; //prints foo
To put this an array just do something like this
把它放在一个数组中，只需做这样的事情
$arr = array($obj->id, $obj->name, $obj->email);
Now you can use this like
现在你可以像这样使用它
$arr[0] // prints 1
回答by Ilya Degtyarenko
You can use json_decode()
您可以使用json_decode()
$json = '{"id":1,"name":"foo","email":"[email protected]"}';
$object = json_decode($json);
Output:
{#775 ▼
+"id": 1
+"name": "foo"
+"email": "[email protected]"
}
How to use:$object->id//1
使用方法：$object->id//1
$array = json_decode($json, true /*[bool $assoc = false]*/);
Output:
array:3 [▼
"id" => 1
"name" => "foo"
"email" => "[email protected]"
]
How to use:$array['id']//1
使用方法：$array['id']//1
