如何在 Java 中组合两个对象数组
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How to combine two object arrays in Java
提问by Oleaha
I have this little script that gets information from an excel file. After I've collected the information that i need i want to combine these two arrays into one. Is that possible?
我有这个从 excel 文件中获取信息的小脚本。在收集了我需要的信息后，我想将这两个数组合并为一个。那可能吗？
public Object[][] createData1() throws Exception {
Object[][] retObjArr1 = data.getTableArray("C:\Users\OAH\Workspaces\Chrome2\Testdata2.xls", "Sheet1", "normalCustomer");
Object[][] retObjArr2 = data.getTableArray("C:\Users\OAH\Workspaces\Chrome2\Testdata2.xls", "Sheet2", "langLogin");
return(retObjArrCombined); //I want to return one array with both arrays
}
回答by systemboot
回答by Michael W
How about this?
这个怎么样？
Link to Another Stack Question!!!!!!
public static int[][] append(int[][] a, int[][] b) {
int[][] result = new int[a.length + b.length][];
System.arraycopy(a, 0, result, 0, a.length);
System.arraycopy(b, 0, result, a.length, b.length);
return result;
}
回答by Dmitry Trifonov
Here is simple solution:
这是简单的解决方案：
private static Object[] concatenate(Object[] a, Object[] b) {
Collection<Object> result = new ArrayList<Object>(a.length + b.length);
for (Object val : a) {
result.add(val);
}
for (Object val : b) {
result.add(val);
}
return result.toArray();
}
回答by Kaplan
one-liner with streams without computation pull ups
and yes it will be a few ms slower
没有计算上拉的单行流
，是的，它会慢几毫秒
Object[][] combi = Stream.concat( Arrays.stream( retObjArr1 ), Arrays.stream( retObjArr2 ) ).toArray( Object[][]::new );
Object[][] combi = Stream.concat( Arrays.stream( retObjArr1 ), Arrays.stream( retObjArr2 ) ).toArray( Object[][]::new );
回答by isvforall
Another way:
其他方式：
Object[][] one = {{1, 2, 3}, {4, 5}, {6}};
Object[][] two = {{7, 8}, {9}};
List<Object[]> holder = new ArrayList<>();
Collections.addAll(holder, one);
Collections.addAll(holder, two);
Object[][] result = holder.toArray(new Object[holder.size()][]);
回答by Visruth
The following code achieves your task :
以下代码可以完成您的任务：
Object[][] retObjArr1 = { { "a00", "a01" }, { "a10", "a11" },
{ "a20", "a21" } };
Object[][] retObjArr2 = { { "b00", "b01" }, { "b10", "b11" },
{ "b20", "b21" } };
List<Object[][]> list = new ArrayList<Object[][]>();
list.add(retObjArr1);
list.add(retObjArr2);
int totalRow = 0;
for (int all = 0; all < list.size(); all++) {
totalRow += list.get(all).length;
}
Object[][] retObjArrCombined = new Object[totalRow][];
int rowCount = 0;
for (int all = 0; all < list.size(); all++) {
Object[][] objects = list.get(all);
for (int i = 0; i < objects.length; i++) {
retObjArrCombined[rowCount] = objects[i];
rowCount++;
}
}
for (int i = 0; i < retObjArrCombined.length; i++) {
for (int j = 0; j < retObjArrCombined[i].length; j++) {
System.out.println("value at :(" + i + "," + j + ") is:"
+ retObjArrCombined[i][j]);
}
}
In this code, the Object[][] retObjArrCombinedcontains all arrays copied from retObjArr1, retObjArr2etc... And it prints the following output :
在这段代码中，Object[][] retObjArrCombined包含了从复制的所有阵列retObjArr1，retObjArr2等...它输出以下：
value at :(0,0) is:a00
value at :(0,1) is:a01
value at :(1,0) is:a10
value at :(1,1) is:a11
value at :(2,0) is:a20
value at :(2,1) is:a21
value at :(3,0) is:b00
value at :(3,1) is:b01
value at :(4,0) is:b10
value at :(4,1) is:b11
value at :(5,0) is:b20
value at :(5,1) is:b21
