Laravel 5 更改表单请求失败的验证行为
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Laravel 5 change form request failed validation behavior
提问by Khalid Dabjan
I have a form request to validate registration data. The application is a mobile API and I would like this class to return formatted JSON in case of a failed validation instead of what it does by default (redirection).
我有一个表单请求来验证注册数据。该应用程序是一个移动 API，我希望这个类在验证失败的情况下返回格式化的 JSON，而不是它默认执行的操作（重定向）。
I tried overriding the method failedValidationfrom Illuminate\Foundation\Http\FormRequestclass. but that doesn't seem to work. Any ideas?
我尝试failedValidation从Illuminate\Foundation\Http\FormRequest类中覆盖该方法。但这似乎不起作用。有任何想法吗？
Code:
代码：
<?php
namespace App\Http\Requests;
use App\Http\Requests\Request;
use Illuminate\Contracts\Validation\Validator;
class RegisterFormRequest extends Request {
/**
* Determine if the user is authorized to make this request.
*
* @return bool
*/
public function authorize() {
return TRUE;
}
/**
* Get the validation rules that apply to the request.
*
* @return array
*/
public function rules() {
return [
'email' => 'email|required|unique:users',
'password' => 'required|min:6',
];
}
}
采纳答案by pinkal vansia
By looking at following function in Illuminate\Foundation\Http\FormRequest, it seems Laravel handles it properly.
通过查看 中的以下函数Illuminate\Foundation\Http\FormRequest，Laravel 似乎可以正确处理它。
/**
* Get the proper failed validation response for the request.
*
* @param array $errors
* @return \Symfony\Component\HttpFoundation\Response
*/
public function response(array $errors)
{
if ($this->ajax() || $this->wantsJson())
{
return new JsonResponse($errors, 422);
}
return $this->redirector->to($this->getRedirectUrl())
->withInput($this->except($this->dontFlash))
->withErrors($errors, $this->errorBag);
}
And as per wantsJsonfunction in Illuminate\Http\Requestbelow, you must explicitly seek JSONresponse,
根据下面的wantsJson功能Illuminate\Http\Request，您必须明确寻求JSON回应，
/**
* Determine if the current request is asking for JSON in return.
*
* @return bool
*/
public function wantsJson()
{
$acceptable = $this->getAcceptableContentTypes();
return isset($acceptable[0]) && $acceptable[0] == 'application/json';
}
回答by Balachandiran
No need override any function. just you add the
无需覆盖任何功能。只需添加
Accept: application/json
In your form header. Laravel will return the response in same URL and in JSON format.
在您的表单标题中。Laravel 将以相同的 URL 和 JSON 格式返回响应。
回答by Kuya A
This is my solution and it is working well in my end. I added the function below Request code:
这是我的解决方案，它最终运行良好。我在请求代码下面添加了函数：
public function response(array $errors)
{
if ($this->ajax() || $this->wantsJson())
{
return Response::json($errors);
}
return $this->redirector->to($this->getRedirectUrl())
->withInput($this->except($this->dontFlash))
->withErrors($errors, $this->errorBag);
}
The response function handle well by laravel. It will automatically return if you request json or ajax.
响应函数由 laravel 处理得很好。如果您请求 json 或 ajax，它将自动返回。
回答by Rahul Gaikwad
Just add the following function on your Request:
只需在您的请求中添加以下功能：
use Response;
public function response(array $errors)
{
return Response::json($errors);
}
