php 注意：遇到格式不正确的数值
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Notice: A non well formed numeric value encountered
提问by Vipin
I have the following code and error. So please give me some suggestion how to resolve this?
我有以下代码和错误。所以请给我一些建议如何解决这个问题？
include('config/setup.php');
$query="select * from tbluser";
$fetch=mysqli_query($connect,$query) or die(mysqli_error($connect));
$row=mysqli_fetch_assoc($fetch);
echo $row['join_date']."</br>";
echo $date=strtotime($row['join_date'])."</br>";
echo $a=date('d-M-Y',$date)
2014-05-04
1399154400
Notice: A non well formed numeric value encountered in C:\xampp\htdocs\flipkart\index.php on line 12 04-May-2014
2014-05-04
1399154400
注意：2014 年 5 月 4 日第 12 行在 C:\xampp\htdocs\flipkart\index.php 中遇到格式不正确的数值
回答by Barmar
When you do:
当你这样做时：
echo $date=strtotime($row['join_date'])."</br>";
You're setting $dateto the string "1399154400</br>". date()expects its second argument to be a number, and this isn't a number because it ends with </br>.
您正在设置$date为 string "1399154400</br>"。date()期望它的第二个参数是一个数字，这不是一个数字，因为它以</br>.
Change it to:
将其更改为：
$date=strtotime($row['join_date']);
echo $date . "<br/>";
or:
或者：
echo $date=strtotime($row['join_date']), "<br/>";
This sends <br/>as a separate argument to echo, rather than concatenating it when doing the assignment.
这将<br/>作为一个单独的参数发送到echo，而不是在进行赋值时连接它。
BTW, the correct tag for line breaks is <br/>, not </br>
顺便说一句，换行符的正确标记是<br/>，而不是</br>
回答by TipuZaynSultan
You are actually Passing the time with the <br />tag...
So $dateis not numeric anymore.
Place it directly inside the date()function...
你实际上是在用<br />标签打发时间......所以$date不再是数字了。直接放在date()函数里面...
include('config/setup.php');
$query="select * from tbluser";
$fetch=mysqli_query($connect,$query) or die(mysqli_error($connect));
$row=mysqli_fetch_assoc($fetch);
echo $row['join_date']."<br />";
echo strtotime($row['join_date'])."<br />";
echo date('d-M-Y', strtotime($row['join_date']));
