C++ lambdas 需要捕获“this”来调用静态成员函数？
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lambdas require capturing 'this' to call static member function?
提问by HighCommander4
For the following code:
对于以下代码：
struct B
{
void g()
{
[]() { B::f(); }();
}
static void f();
};
g++ 4.6 gives the error:
g++ 4.6 给出了错误：
test.cpp: In lambda function:
test.cpp:44:21: error: 'this' was not captured for this lambda function
test.cpp：在 lambda 函数中：
test.cpp:44:21：错误：此 lambda 函数未捕获“this”
(Interestingly, g++ 4.5 compiles the code fine).
（有趣的是，g++ 4.5 编译代码很好）。
Is this a bug in g++ 4.6, or is it really necessary to capture the 'this' parameter to be able to call a static member function? I don't see why it should be, I even qualified the call with B::.
这是 g++ 4.6 中的错误，还是真的有必要捕获“this”参数才能调用静态成员函数？我不明白为什么会这样，我什至用B::.
采纳答案by Mikael Persson
I agree, it should compile just fine. For the fix (if you didn't know already), just add the reference capture and it will compile fine on gcc 4.6
我同意，它应该编译得很好。对于修复（如果您还不知道），只需添加引用捕获，它就可以在 gcc 4.6 上正常编译
struct B
{
void g()
{
[&]() { B::f(); }();
}
static void f() { std::cout << "Hello World" << std::endl; };
};
