C# 从 double 中获取小数部分
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Get the decimal part from a double
提问by user1095549
I want to receive the number after the decimal dot in the form of an integer. For example, only 05 from 1.05 or from 2.50 only 50 not0.50
我想以整数的形式接收小数点后的数字。例如，只有 05 从 1.05 或从 2.50 只有 50而不是0.50
采纳答案by Karthik Krishna Baiju
Updated Answer
更新答案
Here I am giving 3 approaches for the same.
在这里，我给出了 3 种相同的方法。
[1] Math Solution using Math.Truncate
[1] 使用Math.Truncate 的数学解决方案
var float_number = 12.345;
var result = float_number - Math.Truncate(float_number);
// input : 1.05
// output : "0.050000000000000044"
// 输入：1.05
// 输出：“0.050000000000000044”
// input : 10.2
// output : 0.19999999999999929
// 输入：10.2
// 输出：0.19999999999999929
If this is not the result what you are expecting, then you have to change the result to the form which you want (but you might do some string manipulations again.)
如果这不是您所期望的结果，那么您必须将结果更改为您想要的形式（但您可能会再次进行一些字符串操作。）
[2] using multiplier [which is 10 to the power of N (e.g. 102 or 103) where N is the number of decimal places]
[2] 使用乘数 [这是 10 的 N 次方（例如 102 或 103），其中 N 是小数位数]
// multiplier is " 10 to the power of 'N'" where 'N' is the number
// of decimal places
int multiplier = 1000;
double double_value = 12.345;
int double_result = (int)((double_value - (int)double_value) * multiplier);
// output 345
// 输出 345
If the number of decimal places is not fixed, then this approach may create problems.
如果小数位数不固定，则此方法可能会产生问题。
[3] using "Regular Expressions (REGEX)"
[3] 使用“正则表达式（REGEX）”
we should be very careful while writing solutions with string. This would not be preferableexcept some cases.
我们在用字符串编写解决方案时应该非常小心。除某些情况外，这不是可取的。
If you are going to do some string operations with decimal places, then this would be preferable
如果您要进行一些带小数位的字符串操作，那么这将是可取的
string input_decimal_number = "1.50";
var regex = new System.Text.RegularExpressions.Regex("(?<=[\.])[0-9]+");
if (regex.IsMatch(input_decimal_number))
{
string decimal_places = regex.Match(input_decimal_number).Value;
}
// input : "1.05"
// output : "05"
// 输入：“1.05”
// 输出：“05”
// input : "2.50"
// output : "50"
// 输入：“2.50”
// 输出：“50”
// input : "0.0550"
// output : "0550"
// 输入：“0.0550”
// 输出：“0550”
you can find more about Regex on http://www.regexr.com/
您可以在http://www.regexr.com/上找到有关 Regex 的更多信息
回答by tmesser
var decPlaces = (int)(((decimal)number % 1) * 100);
This presumes your number only has two decimal places.
这假设您的数字只有两位小数。
回答by System Down
var result = number.ToString().Split(System.Globalization.NumberDecimalSeparator)[2]
Returns it as a string (but you can always cast that back to an int), and assumes the number does have a "." somewhere.
将其作为字符串返回（但您始终可以将其转换回 int），并假设该数字确实有一个“。” 某处。
回答by swabs
Use a regex: Regex.Match("\.(?\d+)")Someone correct me if I'm wrong here
使用正则表达式：Regex.Match("\.(?\d+)")如果我在这里错了，有人会纠正我
回答by Parag Meshram
Better Way -
更好的方法 -
double value = 10.567;
int result = (int)((value - (int)value) * 100);
Console.WriteLine(result);
Output -
输出 -
56
回答by Picrofo Software
You may remove the dot .from the double you are trying to get the decimals from using the Remove()function after converting the double to string so that you could do the operations required on it
.在将双精度Remove()转换为字符串后，您可以从尝试使用该函数获取小数的双精度中删除点，以便您可以对其进行所需的操作
Consider having a double _Doubleof value of 0.66781, the following code will only show the numbers after the dot .which are 66781
考虑有一个 double_Double的值0.66781，下面的代码将只显示点.后面的数字66781
double _Double = 0.66781; //Declare a new double with a value of 0.66781
string _Decimals = _Double.ToString().Remove(0, _Double.ToString().IndexOf(".") + 1); //Remove everything starting with index 0 and ending at the index of ([the dot .] + 1)
Another Solution
另一种解决方案
You may use the class Pathas well which performs operations on string instances in a cross-platform manner
您也可以使用Path以跨平台方式对字符串实例执行操作的类
double _Double = 0.66781; //Declare a new double with a value of 0.66781
string Output = Path.GetExtension(D.ToString()).Replace(".",""); //Get (the dot and the content after the last dot available and replace the dot with nothing) as a new string object Output
//Do something
回答by Berezh
public static string FractionPart(this double instance)
{
var result = string.Empty;
var ic = CultureInfo.InvariantCulture;
var splits = instance.ToString(ic).Split(new[] { ic.NumberFormat.NumberDecimalSeparator }, StringSplitOptions.RemoveEmptyEntries);
if (splits.Count() > 1)
{
result = splits[1];
}
return result;
}
回答by matterai
the best of the best way is:
最好的方法是：
var floatNumber = 12.5523;
var x = floatNumber - Math.Truncate(floatNumber);
result you can convert however you like
结果你可以随意转换
回答by redditmerc
int last2digits = num - (int) ((double) (num / 100) * 100);
回答by ?a?atay Yap?c?
It is very simple
这很简单
float moveWater = Mathf.PingPong(theTime * speed, 100) * .015f;
int m = (int)(moveWater);
float decimalPart= moveWater -m ;
Debug.Log(decimalPart);
