bash 语法错误：“fi”意外
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Syntax error: "fi" unexpected
提问by mee
I am trying to write a shell script that will either start or stop openvpn, depending on what the user enters. When I run the script it correctly prompts me for what I want to do. But when I type "1" and hit [Enter] it outputs this and terminates:
我正在尝试编写一个 shell 脚本，该脚本将根据用户输入的内容启动或停止 openvpn。当我运行脚本时，它会正确提示我想要做什么。但是当我输入“1”并点击[Enter]时，它会输出这个并终止：
./control-openvpn.sh: 27: ./control-openvpn.sh: Syntax error: "fi" unexpected
Here is the main part of my code. The functions are above it in the script.
这是我的代码的主要部分。函数在脚本中位于其上方。
# Main
echo -n "What to do? 1.Start or 2.Stop. [1/2]"
read action
if [ "$action" == "1" ]
then
start_openvpn()
elif [ "$action" == "2" ]
then
stop_openvpn()
fi
Thank you in advance
先感谢您
采纳答案by Jason Colyer
In bash, when you do start_openvpn(), you are declaring a new function. Thus, bash gets confused when the next thing it sees is fi. Something like this should work for you:
在 bash 中，当您执行 start_openvpn() 时，您是在声明一个新函数。因此，当 bash 看到的下一件事是 fi 时，它会感到困惑。像这样的事情应该适合你：
read -p 'What to do? 1.Start or 2.Stop. [1/2] ' action
if [ $action -eq 1 ]; then
start_openvpn
elif [ $action -eq 2 ]; then
stop_openvpn
fi
