Java 如何使用默认区域解析 ZonedDateTime？
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How to parse ZonedDateTime with default zone?
提问by Sergey Ponomarev
How to parse ZoneDateTimefrom string that doesn't contain zoneand others fields?
如何ZoneDateTime从不包含zone其他字段的字符串中解析？
Here is test in Spock to reproduce:
这是在 Spock 中重现的测试：
import spock.lang.Specification
import spock.lang.Unroll
import java.time.ZoneId
import java.time.ZoneOffset
import java.time.ZonedDateTime
import java.time.format.DateTimeFormatter
@Unroll
class ZonedDateTimeParsingSpec extends Specification {
def "DateTimeFormatter.ISO_ZONED_DATE_TIME parsing incomplete date: #value #expected"() {
expect:
ZonedDateTime.parse(value, DateTimeFormatter.ISO_ZONED_DATE_TIME) == expected
where:
value | expected
'2014-04-23T04:30:45.123Z' | ZonedDateTime.of(2014, 4, 23, 4, 30, 45, 123_000_000, ZoneOffset.UTC)
'2014-04-23T04:30:45.123+01:00' | ZonedDateTime.of(2014, 4, 23, 4, 30, 45, 123_000_000, ZoneOffset.ofHours(1))
'2014-04-23T04:30:45.123' | ZonedDateTime.of(2014, 4, 23, 4, 30, 45, 123_000_000, ZoneId.systemDefault())
'2014-04-23T04:30' | ZonedDateTime.of(2014, 4, 23, 4, 30, 0, 0, ZoneId.systemDefault())
'2014-04-23' | ZonedDateTime.of(2014, 4, 23, 0, 0, 0, 0, ZoneId.systemDefault())
}
}
First two test passed, all others failed with DateTimeParseException:
前两个测试通过了，所有其他测试都失败了 DateTimeParseException：
- '2014-04-23T04:30:45.123' could not be parsed at index 23
- '2014-04-23T04:30' could not be parsed at index 16
- '2014-04-23' could not be parsed at index 10
- 无法在索引 23 处解析“2014-04-23T04:30:45.123”
- 无法在索引 16 处解析“2014-04-23T04:30”
- 无法在索引 10 处解析“2014-04-23”
How can I parse incomplete dates with time and zone setted to default?
如何在时间和区域设置为默认值的情况下解析不完整的日期？
采纳答案by bowmore
Since the ISO_ZONED_DATE_TIMEformatter expects zone or offset information, parsing fails.
You'll have to make a DateTimeFormatterthat has optional parts for both the zone information and the time part.
It's not too hard reverse engineering the ZonedDateTimeFormatterand adding optional tags.
由于ISO_ZONED_DATE_TIME格式化程序需要区域或偏移信息，因此解析失败。您必须制作一个DateTimeFormatter具有区域信息和时间部分的可选部分。逆向工程ZonedDateTimeFormatter和添加可选标签并不太难。
Then you parse the Stringusing the parseBest()method of the formatter. Then, for suboptimal parse results you can create the ZonedDateTimeusing any default you want.
然后你String使用parseBest()格式化程序的方法解析。然后，对于次优的解析结果，您可以ZonedDateTime使用任何您想要的默认值来创建。
DateTimeFormatter formatter = new DateTimeFormatterBuilder()
.parseCaseInsensitive()
.append(ISO_LOCAL_DATE)
.optionalStart() // time made optional
.appendLiteral('T')
.append(ISO_LOCAL_TIME)
.optionalStart() // zone and offset made optional
.appendOffsetId()
.optionalStart()
.appendLiteral('[')
.parseCaseSensitive()
.appendZoneRegionId()
.appendLiteral(']')
.optionalEnd()
.optionalEnd()
.optionalEnd()
.toFormatter();
TemporalAccessor temporalAccessor = formatter.parseBest(value, ZonedDateTime::from, LocalDateTime::from, LocalDate::from);
if (temporalAccessor instanceof ZonedDateTime) {
return ((ZonedDateTime) temporalAccessor);
}
if (temporalAccessor instanceof LocalDateTime) {
return ((LocalDateTime) temporalAccessor).atZone(ZoneId.systemDefault());
}
return ((LocalDate) temporalAccessor).atStartOfDay(ZoneId.systemDefault());
回答by JodaStephen
The formatter has a withZone()methodthat can be called to provide the missing time-zone.
格式化程序有一个withZone()方法可以调用以提供缺少的时区。
ZonedDateTime.parse(
value,
DateTimeFormatter.ISO_ZONED_DATE_TIME.withZone(ZoneId.systemDefault()))
Bear in mind that there was a bug, so you need 8u20 or later for it to work fully.
请记住，存在一个错误，因此您需要 8u20 或更高版本才能使其完全工作。
