获得 php DateInterval 总“分钟”
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get php DateInterval in total 'minutes'
提问by Rana
I am trying to get the PHP "DateInterval" value in "total minutes" value. How to get it? Seems like simple format("%i minutes") not working?
我试图在“总分钟数”值中获取 PHP“DateInterval”值。如何获得？似乎简单的格式（“%i 分钟”）不起作用？
Here is the sample code:
这是示例代码：
$test = new \DateTime("48 hours");
$interval = $test->diff(new \DateTime());
Now if I try to get the interval in total days, its fine:
现在，如果我尝试获得总天数的间隔，那很好：
echo $interval->format('%a total days');
It is showing 2 days as output, which is totally fine. What I am trying to get if to get the value in "total minutes", so I tried:
它显示 2 天作为输出，这完全没问题。如果要在“总分钟数”中获得值，我想得到什么，所以我尝试了：
echo $interval->format('%i total minutes');
Which is not working. Any help appreciated to get my desired output.
哪个不起作用。感谢任何帮助以获得我想要的输出。
回答by deceze
abs((new \DateTime("48 hours"))->getTimestamp() - (new \DateTime)->getTimestamp()) / 60
That's the easiest way to get the difference in minutes between two DateTimeinstances.
这是获得两个DateTime实例之间的分钟差异的最简单方法。
回答by Neil Townsend
If you are stuck in a position where all you have is the DateInterval, and you (like me) discover that there seems to be no way to get the total minutes, seconds or whatever of the interval, the solution is to create a DateTime at zero time, add the interval to it, and then get the resulting timestamp:
如果您被困在只有 的位置DateInterval，并且您（像我一样）发现似乎无法获得总分钟数、秒数或任何时间间隔，解决方案是在零处创建 DateTime时间，将间隔添加到它，然后得到结果时间戳：
$timeInterval = //the DateInterval you have;
$intervalInSeconds = (new DateTime())->setTimeStamp(0)->add($timeInterval)->getTimeStamp();
$intervalInMinutes = $intervalInSeconds/60; // and so on
回答by Genmais
I wrote two functions that just calculates the totalTime from a DateInterval. Accuracy can be increased by considering years and months.
我写了两个函数，它们只是从 DateInterval 计算 totalTime。可以通过考虑年和月来提高精度。
function getTotalMinutes(DateInterval $int){
return ($int->d * 24 * 60) + ($int->h * 60) + $int->i;
}
function getTotalHours(DateInterval $int){
return ($int->d * 24) + $int->h + $int->i / 60;
}
回答by ggallego
That works perfectly.
这完美地工作。
function calculateMinutes(DateInterval $int){
$days = $int->format('%a');
return ($days * 24 * 60) + ($int->h * 60) + $int->i;
}
回答by Sebastian Viereck
Here is the excepted answer as a method in PHP7.2 style:
这是作为 PHP7.2 样式方法的例外答案：
/**
* @param \DateTime $a
* @param \DateTime $b
* @return int
*/
public static function getMinutesDifference(\DateTime $a, \DateTime $b): int
{
return abs($a->getTimestamp() - $b->getTimestamp()) / 60;
}
