Laravel 查询生成器搜索(匹配)
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/38488926/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-09-14 14:11:27 来源:igfitidea点击:
Laravel Query Builder Search (match against)
提问by Marc
I'm trying to write this query in Laravel
我正在尝试在 Laravel 中编写此查询
select *, MATCH(hobbies)AGAINST('soccer') from users where MATCH(hobbies)AGAINST('soccer' IN BOOLEAN MODE) LIMIT 10 OFFSET 0;
I have looked in the documentation on query builder but didn't find anything on full-text search.
我查看了有关查询构建器的文档,但在全文搜索中没有找到任何内容。
Please help.
请帮忙。
Thank you in advance :)
先感谢您 :)
回答by Tang3
User::selectRaw("*, MATCH(hobbies)AGAINST('soccer')")
->whereRaw("MATCH(hobbies)AGAINST('soccer' IN BOOLEAN MODE)")
->limit(10);
回答by Marc
Thanks to Samsquanch he pointed me in the right direction. Here is how I got it done.
感谢 Samsquanch,他为我指明了正确的方向。这是我如何完成的。
$my_query = "select *, MATCH (name) AGAINST (?) from users
where MATCH (hobbies) AGAINST (? IN BOOLEAN MODE) limit 10 OFFSET ?"
$hobbies = DB::select($my_query, array($search_term, $search_term, (($page-1)*10)));