java 使用 * 星打印 Z 形金字塔
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/33172657/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Print a Z shape pyramid using * stars
提问by Kyle
I am trying to write a program that outputs a Z pattern that is nnumber of *across the top, bottom, and connecting line using for loops.
我试图写一个程序，其输出是Z模式n的数量*在顶部，底部，并使用循环连接线。
Example:
例子：
Enter a number: 6
******
*
*
*
*
******
This is my current code, it's producing a half pyramid upside down.
这是我当前的代码，它产生了一个倒置的半金字塔。
import java.util.*;
public class ZShape {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter a number: ");
int n = input.nextInt();
for (int x = 0; x <= n; x++) {
for (int y = n; y >= 1; y--) {
if (y > x) {
System.out.print("* ");
}
else
System.out.print(" ");
}
System.out.println();
}
}
}
回答by Tunaki
This is the logic in the following code:
这是以下代码中的逻辑：
- Loop over each row of the output (so from 0 to
nexcluded so that we havenrows) - Loop over each column of the output (so from 0 to
nexcluded so that we havencolumns) - We need to print a
*only when it is the first row (x == 0) or the last row (x == n - 1) or the column is in the opposite diagonal (column == n - 1 - row)
- 循环输出的每一行（所以从 0 到
n排除，以便我们有n行） - 循环输出的每一列（所以从 0 到
n排除，以便我们有n列） *只有在第一行 (x == 0) 或最后一行 (x == n - 1) 或该列位于对角线 (column == n - 1 - row)时才需要打印 a
Code:
代码：
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter a number: ");
int n = input.nextInt();
for (int row = 0; row < n; row++) {
for (int column = 0; column < n; column++) {
if (row == 0 || row == n - 1 || column == n - 1 - row) {
System.out.print("*");
} else {
System.out.print(" ");
}
}
System.out.println();
}
}
Sample output for n = 6:
示例输出n = 6：
******
*
*
*
*
******
(Note that this output has trailing white-spaces for each row, you did not specify whether they should be included, but it is easy to remove them by adding another check).
（请注意，此输出的每一行都有尾随空格，您没有指定是否应包含它们，但通过添加另一个检查很容易删除它们）。
回答by Ryan
How about using three loops instead?
改用三个循环怎么样？
for (int x = 0; x < n; x++) {
System.out.print("*");
}
System.out.println();
for (int x = n-3; x >= 0; x--) {
for (int y = x; y >= 0; y--) {
System.out.print(" ");
}
System.out.println("*");
}
for (int x = 0; x < n; x++) {
System.out.print("*");
}
回答by Sw?sh S?t?ka?t
public class Star {
public static void main(String[] args) {
for (int i = 0; i <=4; i++) {
for (int j = 0; j <=4; j++)
{
if (i==4 || (i+j)==4 || i==0)
{
System.out.print(" * ");
}
else
{
System.out.print(" ");
}
}
System.out.println(" ");
}
}
}
