Python：获取异常的错误消息
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Python: Getting the error message of an exception
提问by Hellnar
In python 2.6.6, how can I capture the error message of an exception.
在 python 2.6.6 中，如何捕获异常的错误消息。
IE:
IE：
response_dict = {} # contains info to response under a django view.
try:
plan.save()
response_dict.update({'plan_id': plan.id})
except IntegrityError, e: #contains my own custom exception raising with custom messages.
response_dict.update({'error': e})
return HttpResponse(json.dumps(response_dict), mimetype="application/json")
This doesnt seem to work. I get:
这似乎不起作用。我得到：
IntegrityError('Conflicts are not allowed.',) is not JSON serializable
采纳答案by Ignacio Vazquez-Abrams
Pass it through str()first.
先通过吧str()。
response_dict.update({'error': str(e)})
Also note that certain exception classes may have specific attributes that give the exact error.
另请注意，某些异常类可能具有给出确切错误的特定属性。
回答by khachik
Everything about stris correct, yet another answer: an Exceptioninstance has messageattribute, and you may want to use it (if your customized IntegrityErrordoesn't do something special):
一切str都是正确的，还有另一个答案：Exception实例具有message属性，您可能想要使用它（如果您的自定义IntegrityError没有做一些特殊的事情）：
except IntegrityError, e: #contains my own custom exception raising with custom messages.
response_dict.update({'error': e.message})
回答by Don
You should use unicodeinstead of stringif you are going to translate your application.
如果您要翻译您的应用程序，您应该使用unicode而不是string。
BTW, Im case you're using json because of an Ajax request, I suggest you to send errors back with HttpResponseServerErrorrather than HttpResponse:
顺便说一句，如果您因为 Ajax 请求而使用 json，我建议您将错误发送回HttpResponseServerError而不是HttpResponse：
from django.http import HttpResponse, HttpResponseServerError
response_dict = {} # contains info to response under a django view.
try:
plan.save()
response_dict.update({'plan_id': plan.id})
except IntegrityError, e: #contains my own custom exception raising with custom messages.
return HttpResponseServerError(unicode(e))
return HttpResponse(json.dumps(response_dict), mimetype="application/json")
and then manage errors in your Ajax procedure. If you wish I can post some sample code.
然后管理 Ajax 过程中的错误。如果您愿意，我可以发布一些示例代码。
回答by Rick Graves
This works for me:
这对我有用：
def getExceptionMessageFromResponse( oResponse ):
#
'''
exception message is burried in the response object,
here is my struggle to get it out
'''
#
l = oResponse.__dict__['context']
#
oLast = l[-1]
#
dLast = oLast.dicts[-1]
#
return dLast.get( 'exception' )
