javascript 获取特定单词后的文本
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/25639365/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Get the text after a specific word
提问by Wolf
Let say I have the following strings:
假设我有以下字符串：
var Y = "TEST"
var X = "abc 123 TEST 456 def"
I would like to get the string from X that comes after the word that specified in Y.
我想从 X 中获取 Y 中指定的单词之后的字符串。
In this example it will be:
在这个例子中，它将是：
var Z = " 456 def"
回答by VisioN
Probably the fastest way will be to use .slice, .substror .substring:
可能最快的方法是使用.slice,.substr或.substring：
var Z = X.slice(X.indexOf(Y) + Y.length);
However there are some other alternatives, like with regular expressions:
然而，还有一些其他的选择，比如正则表达式：
var Z = X.replace(new RegExp('.*' + Y), '');
Or the one with arrays, proposed by @AustinBrunkhorstin the comments:
或者@AustinBrunkhorst在评论中提出的带有数组的方法：
var Z = X.split(Y).pop();
回答by Greg
This will get you the word 'TEST and any words that occur after'
这会让你得到“测试以及之后出现的任何词”这个词
var word = 'abc 123 TEST 456 def';
var scrubbed = words.replace(/TEST(?= )([ A-Za-z0-9])+/, 'Howdy')
// abc 123 Howdy
