xcode 参数类型“字符串”不符合预期类型“序列”
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Argument type 'String' does not conform to expect type 'Sequence'
提问by Oliver Redeyoff
I am developing a app for ios and I am trying to get each letter of a member of dictionary which I have defined like this :
我正在为 ios 开发一个应用程序，我正在尝试获取我定义的字典成员的每个字母：
var Morse = ["a": "01", "b": "1000", "c": "1010", "d": "100", "e": "0", "f": "0010", "g": "110", "h": "0000", "i": "00", "j": "0111", "k": "101", "l": "0100", "m": "11", "n": "10", "o": "111", "p": "0110", "q": "1101", "r": "010", "s": "000", "t": "1", "u": "001", "v": "0001", "w": "011", "x": "1001", "y": "1011", "z": "1100", "1": "01111", "2": "00111", "3": "00011", "4": "00001", "5": "00000", "6": "10000", "7": "11000", "8": "11100", "9": "11110", "0": "11111", " ": "2"]
So for example, if the user enters a I would like to get "0" and then "1". To do this I use a counter :
因此，例如，如果用户输入 a I would like to get "0" 然后是 "1"。为此，我使用了一个计数器：
var counter = 0
var letter: String = ""
var strings_letter: String = ""
letter = Morse[strings_letter]!
var number = Array(letter)[counter]
But this gives me an issue :
但这给了我一个问题：
Argument type 'String' does not conform to expect type 'Sequence'
What am I doing wrong?
我究竟做错了什么？
回答by dfri
The charactersproperty of a Stringinstance contains a sequence of the characters contained in the String. You could, for a given key (say "a") re-map the .charactersof the corresponding value ("01") to single-character Stringinstances to obtain a Stringarray:
实例的characters属性String包含包含在String. 对于给定的键（例如"a"），您可以.characters将相应值（"01"）的重新映射到单字符String实例以获取String数组：
if let charsForKeyA = Morse["a"]?.characters.map({ String("a" => ["0", "1"]
"b" => ["1", "0", "0", "0"]
"c" => ["1", "0", "1", "0"]
) }) {
charsForKeyA.forEach { print(var Morse = ["a": "01", "b": "1000", "c": "1010", "d": "100", "e": "0", "f": "0010", "g": "110", "h": "0000", "i": "00", "j": "0111", "k": "101", "l": "0100", "m": "11", "n": "10", "o": "111", "p": "0110", "q": "1101", "r": "010", "s": "000", "t": "1", "u": "001", "v": "0001", "w": "011", "x": "1001", "y": "1011", "z": "1100", "1": "01111", "2": "00111", "3": "00011", "4": "00001", "5": "00000", "6": "10000", "7": "11000", "8": "11100", "9": "11110", "0": "11111", " ": "2"]
let insertedKey = "a"
if let value = Morse[insertedKey] {
let array = Array(value.characters)
// here is your array!
print(array) // ["0", "1"]
}
) }
} /* 0
1 */
回答by Ahmad F
If I got it right, you want to get an array of characters for the value of the inserted key, based on your example, the output should be like:
如果我猜对了，您想根据您的示例获取插入键值的字符数组，输出应如下所示：
##代码##and so on...
等等...
##代码##