php 字符串到 DateTime 对象
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String to DateTime Object
提问by MAB
I'm new at String functions, so I need a complex substr and trim functions for this string:
我是字符串函数的新手,所以我需要一个复杂的 substr 和 trim 函数来处理这个字符串:
Wed, 28 Dec 2011 13:04:30 GMT
String comes to me always with this format. I want to convert it to DateTime object. Anybody can help me?
字符串总是以这种格式出现在我面前。我想将它转换为 DateTime 对象。任何人都可以帮助我吗?
回答by Mark Baker
$dateString = 'Wed, 28 Dec 2011 13:04:30 GMT';
$dateTime = datetime::createfromformat('D, d M Y H:i:s e',$dateString);
echo $dateTime->format('d-M-Y H:i:s e');
回答by álvaro González
<?php
$date = new DateTime('Wed, 28 Dec 2011 13:04:30 GMT');
echo $date->format('r');
... prints:
... 印刷:
Wed, 28 Dec 2011 13:04:30 +0000
回答by Robert Saylor
If you are wanting to take a date string and write that to the database as a date object using Doctrine:
如果您想获取日期字符串并使用 Doctrine 将其作为日期对象写入数据库:
Note: This is a form post example for Symfony 3 and 4.
注意:这是 Symfony 3 和 4 的表单发布示例。
$mynewdateobject = new \DateTime($request->request->get('mydatestring'));
Then you can write the object to the database or use it elsewhere in your code.
然后您可以将对象写入数据库或在代码中的其他地方使用它。