Ruby-on-rails Rails：如何根据控制器类名获取模型类名？
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Rails: How to get the model class name based on the controller class name?
提问by Misha Moroshko
class HouseBuyersController < ...
def my_method
# How could I get here the relevant model name, i.e. "HouseBuyer" ?
end
end
回答by malclocke
This will do it:
这将做到：
class HouseBuyersController < ApplicationController
def index
@model_name = controller_name.classify
end
end
This is often needed when abstracting controller actions:
这在抽象控制器操作时经常需要：
class HouseBuyersController < ApplicationController
def index
# Equivalent of @house_buyers = HouseBuyer.find(:all)
objects = controller_name.classify.constantize.find(:all)
instance_variable_set("@#{controller_name}", objects)
end
end
回答by Matt
If your controller and model are in the same namespace, then what you want is
如果您的控制器和模型在同一个命名空间中，那么您想要的是
controller_path.classify
controller_pathgives you the namespace; controller_namedoesn't.
controller_path给你命名空间；controller_name没有。
For example, if your controller is
例如，如果您的控制器是
Admin::RolesController
then:
然后：
controller_path.classify # "Admin::Role" # CORRECT
controller_name.classify # "Role" # INCORRECT
回答by Scott
It's a bit of a hack, but if your model is named after your controller name then:
这有点黑客，但如果您的模型以您的控制器名称命名，那么：
class HouseBuyersController < ApplicationController
def my_method
@model_name = self.class.name.sub("Controller", "").singularize
end
end
... would give you "HouseBuyer" in your @model_name instance variable.
...会在您的@model_name 实例变量中为您提供“HouseBuyer”。
Again, this makes a huge assumption that "HouseBuyersController" only deals with "HouseBuyer" models.
同样，这做出了一个巨大的假设，即“HouseBuyersController”只处理“HouseBuyer”模型。
回答by hachpai
For namespaces working:
对于命名空间工作：
def resource_class
controller_path.classify.constantize
end
回答by thenengah
This is not possible if you are using the default MVC, which your code doesn't seem to follow. Your controller seems to be a model but maybe you just got a type there. Anyway, controllers and models are fundamentally separated in Rails MVC so controllers cannot know which model they are associated with.
如果您使用的是默认 MVC，这是不可能的，您的代码似乎没有遵循。您的控制器似乎是一个模型，但也许您只是在那里得到了一个类型。无论如何，控制器和模型在 Rails MVC 中从根本上是分开的，因此控制器无法知道它们与哪个模型相关联。
For example you could have a model named post. This can have a controller posts_controller or could have a controller like articles_controller. Rails only knows about models when you def the actual code in the controller such as
例如，您可以有一个名为 post 的模型。这可以有一个控制器posts_controller 或可以有一个控制器，如articles_controller。Rails 仅在您定义控制器中的实际代码时才知道模型，例如
def index
@posts = Post.all
@posts = Article.all
end
In rails standard controllers there is no way to know what the model is.
在 rails 标准控制器中，无法知道模型是什么。
回答by stoffus
The accepted solution did not work for me as my controller and model was namespaced. Instead, I came up with the following method:
接受的解决方案对我不起作用，因为我的控制器和模型是命名空间的。相反，我想出了以下方法：
def controllers_model
(self.class.name.split('::')[0..-2] << controller_name.classify).join('::')
end
