Linux grep 不显示路径/文件：行
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grep without showing path/file:line
提问by Allan Thomas
How do you grep and only return the matching line? i.e. The path/filename is omitted from the results.
你如何 grep 并只返回匹配的行？即结果中省略了路径/文件名。
In this case I want to look in all .bar files in the current directory, searching for the term FOO
在这种情况下，我想查看当前目录中的所有 .bar 文件，搜索术语 FOO
find . -name '*.bar' -exec grep -Hn FOO {} \;
采纳答案by fedorqui 'SO stop harming'
No need to find. If you are just looking for a pattern within a specific directory, this should suffice:
没有必要find。如果您只是在特定目录中寻找模式，这应该就足够了：
grep -hn FOO /your/path/*.bar
Where -his the parameter to hide the filename, as from man grep:
-h隐藏文件名的参数在哪里，从man grep：
-h, --no-filename
Suppress the prefixing of file names on output. This is the default when there is only one file (or only standard input) to search.
-h, --no-文件名
禁止输出文件名的前缀。当只有一个文件（或只有标准输入）要搜索时，这是默认设置。
Note that you were using
请注意，您正在使用
-H, --with-filename
Print the file name for each match. This is the default when there is more than one file to search.
-H, --with-filename
打印每个匹配项的文件名。这是要搜索多个文件时的默认设置。
回答by TC1
From the man page:
从手册页：
-h, --no-filename
Suppress the prefixing of file names on output. This is the default when there
is only one file (or only standard input) to search.
回答by jkshah
Just replace -Hwith -h. Check man grepfor more details on options
只需替换-H为-h. 检查man grep有关选项的更多详细信息
find . -name '*.bar' -exec grep -hn FOO {} \;
