bash 查找包含给定文本的文件
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Find files containing a given text
提问by Owen
In bash I want to return file name (and the path to the file) for every file of type .php|.html|.jscontaining the case-insensitive string "document.cookie" | "setcookie"
在 bash 中，我想为.php|.html|.js包含不区分大小写的字符串的每个类型的文件返回文件名（以及文件的路径）"document.cookie" | "setcookie"
How would I do that?
我该怎么做？
回答by bear24rw
egrep -ir --include=*.{php,html,js} "(document.cookie|setcookie)" .
The rflag means to search recursively (search subdirectories). The iflag means case insensitive.
该r标志表示递归搜索（搜索子目录）。该i标志表示不区分大小写。
If you just want file names add the l(lowercase L) flag:
如果您只想要文件名，请添加l（小写L）标志：
egrep -lir --include=*.{php,html,js} "(document.cookie|setcookie)" .
回答by Raoul
Try something like grep -r -n -i --include="*.html *.php *.js" searchstrinhere .
尝试类似的东西 grep -r -n -i --include="*.html *.php *.js" searchstrinhere .
the -imakes it case insensitlve
这-i使它不区分大小写
the .at the end means you want to start from your current directory, this could be substituted with any directory.
在.你想从你的当前目录开始结束手段，这可以与任何目录取代。
the -rmeans do this recursively, right down the directory tree
该-r方法递归地执行此操作，就在目录树的下方
the -nprints the line number for matches.
在-n打印匹配项的行号。
the --includelets you add file names, extensions. Wildcards accepted
将--include让你添加的文件名，扩展名。接受通配符
For more info see: http://www.gnu.org/software/grep/
有关更多信息，请参阅：http: //www.gnu.org/software/grep/
回答by Michael Berkowski
findthem and grepfor the string:
find他们和grep字符串：
This will find all files of your 3 types in /starting/path and grep for the regular expression '(document\.cookie|setcookie)'. Split over 2 lines with the backslash just for readability...
这将在 /starting/path 和 grep 中找到 3 种类型的所有文件，用于正则表达式'(document\.cookie|setcookie)'。用反斜杠分成 2 行只是为了便于阅读......
find /starting/path -type f -name "*.php" -o -name "*.html" -o -name "*.js" | \
xargs egrep -i '(document\.cookie|setcookie)'
回答by Fredrik Pihl
回答by nos
find . -type f -name '*php' -o -name '*js' -o -name '*html' |\
xargs grep -liE 'document\.cookie|setcookie'
回答by Pedro Vernetti
Just to include one more alternative, you could also use this:
只是为了包括一个更多的选择，你也可以使用这个：
find "/starting/path" -type f -regextype posix-extended -regex "^.*\.(php|html|js)$" -exec grep -EH '(document\.cookie|setcookie)' {} \;
find "/starting/path" -type f -regextype posix-extended -regex "^.*\.(php|html|js)$" -exec grep -EH '(document\.cookie|setcookie)' {} \;
Where:
在哪里：
-regextype posix-extendedtellsfindwhat kind of regex to expect-regex "^.*\.(php|html|js)$"tellsfindthe regex itself filenames must match-exec grep -EH '(document\.cookie|setcookie)' {} \;tellsfindto run the command (with its options and arguments) specified between the-execoption and the\;for each file it finds, where{}represents where the file path goes in this command.while
Eoption tellsgrepto use extended regex (to support the parentheses) and...Hoption tellsgrepto print file paths before the matches.
-regextype posix-extended告诉find期望什么样的正则表达式-regex "^.*\.(php|html|js)$"告诉find正则表达式本身文件名必须匹配-exec grep -EH '(document\.cookie|setcookie)' {} \;告诉find运行在-exec选项和\;它找到的每个文件之间指定的命令（及其选项和参数），其中{}表示文件路径在此命令中的位置。尽管
E选项告诉grep使用扩展正则表达式（以支持括号）和...H选项告诉grep在匹配之前打印文件路径。
And, given this, if you only want file paths, you may use:
并且，鉴于此，如果您只想要文件路径，则可以使用：
find "/starting/path" -type f -regextype posix-extended -regex "^.*\.(php|html|js)$" -exec grep -EH '(document\.cookie|setcookie)' {} \; | sed -r 's/(^.*):.*$/\1/' | sort -u
find "/starting/path" -type f -regextype posix-extended -regex "^.*\.(php|html|js)$" -exec grep -EH '(document\.cookie|setcookie)' {} \; | sed -r 's/(^.*):.*$/\1/' | sort -u
Where
在哪里
|[pipe] send the output offindto the next command after this (which issed, thensort)roption tellssedto use extended regex.s/HI/BYE/tellssedto replace every First occurrence (per line) of "HI" with "BYE" and...s/(^.*):.*$/\1/tells it to replace the regex(^.*):.*$(meaning a group[stuff enclosed by()] including everything[.*= one or more of any-character] from the beginning of the line[^] till' the first ':' followed by anythingtill' the end of line[$]) by the first group[\1] of the replaced regex.utells sort to remove duplicate entries (takesort -uas optional).
|[pipe] 将 的输出发送find到此之后的下一个命令（即sed, thensort）r选项告诉sed使用扩展的正则表达式。s/HI/BYE/告诉sed将“HI”的每个第一次出现（每行）替换为“BYE”，然后......s/(^.*):.*$/\1/告诉它来代替正则表达式(^.*):.*$（意味着组[东西由包围()]，包括一切[.*从=一个或多个任意的字符的]的行的开头[^]直到“第一‘：’随后任何直到”的的端行[$]) 由替换的正则表达式的第一组[\1] 组成。u告诉 sort 删除重复条目（sort -u作为可选）。
...FAR from being the most elegant way. As I said, my intention is to increase the range of possibilities (and also to give more complete explanations on some tools you could use).
...远不是最优雅的方式。正如我所说，我的目的是增加可能性的范围（并且还对您可以使用的一些工具进行更完整的解释）。
