bash 如何将多行文本转换为一行？
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How do I convert multi line text into one line?
提问by john
I'm trying to make a txt file with a generated key into 1 line. example:
我正在尝试将一个带有生成密钥的 txt 文件分成 1 行。例子：
<----- key start ----->
lkdjasdjskdjaskdjasdkj
skdhfjlkdfjlkdsfjsdlfk
kldshfjlsdhjfksdhfksdj
jdhsfkjsdhfksdjfhskdfh
jhdfkjsdhfkjsdhfkjsdhf
<----- key stop ----->
I want it to look like:
我希望它看起来像：
lkdjasdjskdjaskdjasdkjskdhfjlkdfjlkdsfjsdlfkkldshfjlsdhjfksdhfksdjjdhsfkjsdhfksdjfhskdfhjhdfkjsdhfkjsdhfkjsdhf
Notice I also want the lines <----- key start ----->and <----- key stop ----->removed. How can I do this? Would this be done with sed?
请注意我也想行<----- key start ----->和<----- key stop ----->删除。我怎样才能做到这一点？这会完成sed吗？
回答by Luke
回答by Axel Bregnsbo
To convert multi line output to a single space separated line, use
要将多行输出转换为单个空格分隔的行，请使用
tr '\n' ' ' < key.txt
I know this does not answer the detailed question. But it is one possible answer to the title. I needed this answer and my google search found this question.
我知道这不能回答详细的问题。但这是标题的一种可能答案。我需要这个答案，我的谷歌搜索找到了这个问题。
回答by Costa
If you're looking for everything you asked for in one sed, I have this...
如果你在一个 sed 中寻找你想要的一切，我有这个......
sed -n '1h;2,$H;${g;s/\n//g;s/<----- key \(start\|stop\) ----->//g;p}' key.txt
sed -n '1h;2,$H;${g;s/\n//g;s/<----- key \(start\|stop\) ----->//g;p}' key.txt
But it's not exactly easily readable :) If you don't mind piping a couple of commands, you could use the piped grep, tr, sed, etc. suggestions in the rest of the answers you got.
但这并不是很容易阅读 :) 如果您不介意管道化几个命令，则可以在您得到的其余答案中使用管道化的 grep、tr、sed 等建议。
回答by Daniel Haley
grep '^[^<]' test.txt | tr -d '\n'
回答by potong
This might work for you (GNU sed):
这可能对你有用（GNU sed）：
sed -r '/key start/{:a;N;/key stop/!ba;s/^[^\n]*\n(.*)\n.*//;s/\n//g}' file
Gather up lines between key startand key stop. Then remove the first and last lines and delete any newlines.
收集key start和之间的线key stop。然后删除第一行和最后一行并删除所有换行符。
回答by glenn Hymanman
awk '/ key (start|stop) / {next} {printf("%s", str='
aaaaa
<----- key start ----->
lkdjasdjskdjaskdjasdkj
skdhfjlkdfjlkdsfjsdlfk
kldshfjlsdhjfksdhfksdj
jdhsfkjsdhfksdjfhskdfh
jhdfkjsdhfkjsdhfkjsdhf
<----- key stop ----->
bbbbb
'
# for in-place file editing use "ed -s file" and replace ",p" with "w"
# cf. http://wiki.bash-hackers.org/howto/edit-ed
cat <<-'EOF' | sed -e 's/^ *//' -e 's/ *$//' | ed -s <(echo "$str")
H
/<----- key start ----->/+1,/<----- key stop ----->/-1j
/<----- key start ----->/d
/<----- key stop ----->/d
,p
q
EOF
# print the joined lines to stdout only
cat <<-'EOF' | sed -e 's/^ *//' -e 's/ *$//' | ed -s <(echo "$str")
H
/<----- key start ----->/+1,/<----- key stop ----->/-1jp
q
EOF
)} END {print ""}' filename
回答by kuriouscoder
An easy way would be to use cat file.txt | tr -d '\n'
一个简单的方法是使用 cat file.txt | tr -d '\n'
回答by Milimetric
In vim, it's just :%s/^M//
在 vim 中，它只是 :%s/^M//
I use this all the time to generate comma separated lists from lines. For sed or awk, check out the many solutions at this link:
我一直使用它从行中生成逗号分隔的列表。对于 sed 或 awk，请查看此链接中的许多解决方案：
http://www.unix.com/shell-programming-scripting/35107-remove-line-break.html
http://www.unix.com/shell-programming-scripting/35107-remove-line-break.html
Example:
例子：
paste -s -d',' tmpfile | sed 's/,/, /g'
粘贴 -s -d',' tmpfile | sed 's/,/, /g'
回答by karl
You may use man 1 edto join lines as well:
您也可以使用man 1 ed连接线：
grep -v -e "key start" -e "key stop" /PATH_TO/key | tr -d '\n'
