在 python matplotlib 中绘制 (x, y) 坐标列表
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Plotting a list of (x, y) coordinates in python matplotlib
提问by CodeKingPlusPlus
I have a list of pairs (a, b)that I would like to plot with matplotlibin python as actual x-y coordinates. Currently, it is making two plots, where the index of the list gives the x-coordinate, and the first plot's y values are the as in the pairs and the second plot's y values are the bs in the pairs.
我有一个(a, b)我想matplotlib在 python 中作为实际 xy 坐标绘制的对列表。目前，它正在制作两个图，其中列表的索引给出了 x 坐标，第一个图的 y 值是a成对中的s，第二个图的 y 值是b成对中的s。
To clarify, my data looks like this: li = [(a,b), (c,d), ... , (t, u)]I want to do a one-liner that just calls plt.plot()incorrect.
If I didn't require a one-liner I could trivially do:
澄清一下，我的数据如下所示：li = [(a,b), (c,d), ... , (t, u)]我想做一个单线，只是调用plt.plot()不正确。如果我不需要单线，我可以简单地做：
xs = [x[0] for x in li]
ys = [x[1] for x in li]
plt.plot(xs, ys)
- How can I get matplotlib to plot these pairs as x-y coordinates?
- 如何让 matplotlib 将这些对绘制为 xy 坐标？
Thanks for all the help!
感谢所有的帮助！
采纳答案by sashkello
As per this example:
根据这个例子：
import numpy as np
import matplotlib.pyplot as plt
N = 50
x = np.random.rand(N)
y = np.random.rand(N)
plt.scatter(x, y)
plt.show()
will produce:
将产生：
To unpack your data from pairs into lists use zip:
要将您的数据从成对中解压缩到列表中，请使用zip：
x, y = zip(*li)
So, the one-liner:
所以，单线：
plt.scatter(*zip(*li))
回答by Shubham Rana
If you want to plot a single line connecting all the points in the list
如果您想绘制一条连接列表中所有点的线
plt . plot ( li [ : ] )
plt . show ( )
This will plot a line connecting all the pairs in the list as points on a Cartesian plane from the starting of the list to the end. I hope that this is what you wanted.
这将绘制一条连接列表中所有对的线，作为笛卡尔平面上从列表开始到结束的点。我希望这就是你想要的。
回答by Zweedeend
If you have a numpy array you can do this:
如果你有一个 numpy 数组，你可以这样做：
import numpy as np
from matplotlib import pyplot as plt
data = np.array([
[1, 2],
[2, 3],
[3, 6],
])
x, y = data.T
plt.scatter(x,y)
plt.show()
