pandas 来自熊猫数据框的多列的散点图
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Scatter plot from multiple columns of a pandas dataframe
提问by kkhatri99
I have a pandas dataframe that looks as below:
我有一个如下所示的Pandas数据框：
Filename GalCer(18:1/12:0)_IS GalCer(d18:1/16:0) GalCer(d18:1/18:0)
0 A-1-1 15.0 1.299366 40.662458 0.242658 6.891069 0.180315
1 A-1-2 15.0 1.341638 50.237734 0.270351 8.367316 0.233468
2 A-1-3 15.0 1.583500 47.039423 0.241681 7.902761 0.201153
3 A-1-4 15.0 1.635365 53.139610 0.322680 9.578195 0.345681
4 B-1-10 15.0 2.370330 80.209846 0.463770 13.729810 0.395355
I am trying to plot a scatter sub-plots with a shared x-axis with the first column "Filename" on the x-axis. While I am able to generate barplots, the following code gives me a key error for a scatter plot:
我正在尝试使用共享 x 轴绘制散点子图，其中 x 轴上的第一列“文件名”。虽然我能够生成条形图，但以下代码为我提供了散点图的关键错误：
import matplotlib.pyplot as plt
colnames = list (qqq.columns)
qqq.plot.scatter(x=qqq.Filename, y=colnames[1:], legend=False, subplots = True, sharex = True, figsize = (10,50))
KeyError: "['A-1-1' 'A-1-2' 'A-1-3' 'A-1-4' 'B-1-10' ] not in index"
The following code for barplots works fine. Do I need to specify something differently for the scatterplots?
下面的条形图代码工作正常。我是否需要为散点图指定不同的内容？
import matplotlib.pyplot as plt
colnames = list (qqq.columns)
qqq.plot(x=qqq.Filename, y=colnames[1:], kind = 'bar', legend=False, subplots = True, sharex = True, figsize = (10,30))
回答by ImportanceOfBeingErnest
A scatter plot will require numeric values for both axes. In this case you can use the index as x values,
散点图将需要两个轴的数值。在这种情况下，您可以使用索引作为 x 值，
df.reset_index().plot(x="index", y="other column")
The problem is now that you cannot plot several columns at once using the scatter plot wrapper in pandas. Depending on what the reason for using a scatter plot are, you may decide to use a line plot instead, just without lines. I.e. you may specify linestyle="none"and marker="o"to the plot, such that points appear on the plot.
现在的问题是您无法使用 Pandas 中的散点图包装器一次绘制多列。根据使用散点图的原因，您可能决定使用线图代替，只是没有线。即，您可以指定linestyle="none"和marker="o"到绘图，以便点出现在绘图上。
import matplotlib.pyplot as plt
import pandas as pd
import numpy as np
fn = ["{}_{}".format(i,j) for i in list("ABCD") for j in range(4)]
df = pd.DataFrame(np.random.rand(len(fn), 4), columns=list("ZXYQ"))
df.insert(0,"Filename",pd.Series(fn))
colnames = list (df.columns)
df.reset_index().plot(x="index", y=colnames[1:], kind = 'line', legend=False,
subplots = True, sharex = True, figsize = (5.5,4), ls="none", marker="o")
plt.show()
In case you absolutely need a scatter plot, you may create a subplots grid first and then iterate over the columns and axes to plot one scatter plot at a time to the respective axes.
如果您绝对需要散点图，您可以先创建一个子图网格，然后遍历列和轴，一次将一个散点图绘制到相应的轴上。
import matplotlib.pyplot as plt
import pandas as pd
import numpy as np
fn = ["{}_{}".format(i,j) for i in list("ABCD") for j in range(4)]
df = pd.DataFrame(np.random.rand(len(fn), 4), columns=list("ZXYQ"))
df.insert(0,"Filename",pd.Series(fn))
colnames = list (df.columns)
fig, axes = plt.subplots(nrows=len(colnames)-1, sharex = True,figsize = (5.5,4),)
for i, ax in enumerate(axes):
df.reset_index().plot(x="index", y=colnames[i+1], kind = 'scatter', legend=False,
ax=ax, c=colnames[i+1], cmap="inferno")
plt.show()
