php 如何打印_r $_POST 数组？
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How to print_r $_POST array?
提问by Iladarsda
I have following table.
我有下表。
<form method="post" action="test.php">
<input name="id[]" type="text" value="ID1" />
<input name="value[]" type="text" value="Value1" />
<hr />
<input name="id[]" type="text" value="ID2" />
<input name="value[]" type="text" value="Value2" />
<hr />
<input name="id[]" type="text" value="ID3" />
<input name="value[]" type="text" value="Value3" />
<hr />
<input name="id[]" type="text" value="ID4" />
<input name="value[]" type="text" value="Value4" />
<hr />
<input type="submit" />
</form>
And test.php file
和 test.php 文件
<?php
$myarray = array( $_POST);
foreach ($myarray as $key => $value)
{
echo "<p>".$key."</p>";
echo "<p>".$value."</p>";
echo "<hr />";
}
?>
But it is only returning this: <p>0</p><p>Array</p><hr />
但它只返回这个： <p>0</p><p>Array</p><hr />
What I'm doing wrong?
我做错了什么？
回答by billrichards
The foreach loops work just fine, but you can also simply
foreach 循环工作得很好，但您也可以简单地
print_r($_POST);
Or for pretty printing in a browser:
或者在浏览器中进行漂亮的打印：
echo "<pre>";
print_r($_POST);
echo "</pre>";
回答by Senad Me?kin
<?php
foreach ($_POST as $key => $value) {
echo '<p>'.$key.'</p>';
foreach($value as $k => $v)
{
echo '<p>'.$k.'</p>';
echo '<p>'.$v.'</p>';
echo '<hr />';
}
}
?>
this will work, your first solution is trying to print array, because your value is an array.
这会起作用，您的第一个解决方案是尝试打印数组，因为您的值是一个数组。
回答by Brian Driscoll
$_POST is already an array, so you don't need to wrap array() around it.
$_POST 已经是一个数组，所以你不需要用 array() 包裹它。
Try this instead:
试试这个：
<?php
for ($i=0;$i<count($_POST['id']);$i++) {
echo "<p>".$_POST['id'][$i]."</p>";
echo "<p>".$_POST['value'][$i]."</p>";
echo "<hr />";
}
?>
NOTE:This works because your idand valuearrays are symmetrical. If they had different numbers of elements then you'd need to take a different approach.
注意：这是有效的，因为您的id和value数组是对称的。如果他们有不同数量的元素，那么你需要采取不同的方法。
回答by Phil
Why are you wrapping the $_POSTarray in an array?
为什么要将$_POST数组包装在数组中？
You can access your "id" and "value" arrays using the following
您可以使用以下方法访问“id”和“value”数组
// assuming the appropriate isset() checks for $_POST['id'] and $_POST['value']
$ids = $_POST['id'];
$values = $_POST['value'];
foreach ($ids as $idx => $id) {
// ...
}
foreach ($values as $idx => $value) {
// ...
}
回答by Michael Berkowski
You are adding the $_POSTarray as the first element to $myarray. If you wish to reference it, just do:
您将$_POST数组作为第一个元素添加到$myarray. 如果您想引用它，只需执行以下操作：
$myarray = $_POST;
However, this is probably not necessary, as you can just call it via $_POSTin your script.
但是，这可能不是必需的，因为您可以通过$_POST在脚本中调用它。
回答by Headshota
Just:
只是：
foreach ( $_POST as $key => $value) {
echo "<p>".$key."</p>";
echo "<p>".$value."</p>";
echo "<hr />";
}
回答by cwallenpoole
Because you have nested arrays, then I actually recommend a recursive approach:
因为你有嵌套数组，所以我实际上推荐一种递归方法：
function recurse_into_array( $in, $tabs = "" )
{
foreach( $in as $key => $item )
{
echo $tabs . $key . ' => ';
if( is_array( $item ) )
{
recurse_into_array( $item, $tabs . "\t" );
}
else
{
echo $tabs . "\t" . $key;
}
}
}
recurse_into_array( $_POST );
回答by Gopalakrishna Palem
Came across this 'implode' recently.
最近遇到了这个“内爆”。
May be useful to output arrays. http://in2.php.net/implode
可能对输出数组有用。http://in2.php.net/implode
echo 'Variables: ' . implode( ', ', $_POST);
回答by klennepette
$_POSTis an array in itsself you don't need to make an array out of it. What you did is nest the $_POSTarray inside a new array. This is why you print Array.
Change it to:
$_POST本身就是一个数组，您不需要从中创建一个数组。您所做的是将$_POST数组嵌套在新数组中。这就是您打印Array. 将其更改为：
foreach ($_POST as $key => $value) {
echo "<p>".$key."</p>";
echo "<p>".$value."</p>";
echo "<hr />";
}
回答by mingos
$_POST is already an array. Try this:
$_POST 已经是一个数组。尝试这个：
foreach ($_POST as $key => $value) {
echo "<p>".$key."</p>";
echo "<p>".$value."</p>";
echo "<hr />";
}
