Pluck id（整数）转换为字符串 Laravel
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Pluck id (integer) cast to string Laravel
提问by Sagar Chamling
While plucking from a database, I get idas strings.
从数据库中提取时，我得到id字符串。
$alphabets = new Alphabet();
return $alphabets->pluck('name', 'id');
Output
输出
{
"1": "Apple",
"2": "Ball",
"3": "Cat"
}
Expected
预期的
{
1: "Apple",
2: "Ball",
3: "Cat"
}
But, when I reverse IDand name,
但是，当我反转ID和时name，
return $alphabets->pluck('id', 'name');
I get id as integer.
我得到 id 作为整数。
{
"Apple": 1,
"Ball": 2,
"Cat": 3
}
I'm not sure what's happening behind the scene. But how can I get ID in integer ? Actually, old flash session doesn't set value because of 1 vs "1"in Form Collective.
我不确定幕后发生了什么。但是我怎样才能得到整数 ID？实际上，由于1 vs "1"在 Form Collective 中，旧的 Flash 会话没有设置值。
{!! Form::select('alphabet', $alphabets, null, ['class' => 'form-control', 'multiple' => true]) !!}
采纳答案by Sagar Chamling
I think I found the answer here.
我想我在这里找到了答案。
https://laracasts.com/discuss/channels/laravel/pluck-id-integer-cast-to-string
https://laracasts.com/discuss/channels/laravel/pluck-id-integer-cast-to-string
Here I found JSON only allows key names to be strings.
在这里我发现 JSON 只允许键名是字符串。
Using number as "index" (JSON)
{
"1": "Apple",
"2": "Ball",
"3": "Cat"
}
Actually, I want to achieve it for Form Collective. It was a bug and it's PR has been merged now.
实际上，我想为Form Collective. 这是一个错误，现在它的 PR 已经合并。
https://github.com/LaravelCollective/html/pull/368#pullrequestreview-46820423
https://github.com/LaravelCollective/html/pull/368#pullrequestreview-46820423
回答by Dharmesh Rakholia
Try this code
试试这个代码
$alphabets = new Alphabet();
return $alphabets->all()->pluck('name', 'id');
Alphabet.php
字母表.php
You should cast your columns like this.
你应该像这样投射你的专栏。
protected $casts = [
'id' => 'integer',
'name' => 'string'
];
回答by Shailesh Ladumor
you also convert key into int
您还将密钥转换为 int
$alphabets = new Alphabet();
$alphaArr =$alphabets->pluck('name', 'id');
foreach($array as $key => $value) {
$newArray[(int) $key] = $value;
}
回答by Sagar Chamling
Adding this line fix the old session issue of LaravelCollective/Html.
添加此行修复了 LaravelCollective/Html 的旧会话问题。
|| in_array((string) $value, $selected, true)
|| in_array((string) $value, $selected, true)
/**
* Determine if the value is selected.
*
* @param string $value
* @param string $selected
*
* @return null|string
*/
protected function getSelectedValue($value, $selected)
{
if (is_array($selected)) {
return in_array($value, $selected, true) || in_array((string) $value, $selected, true) ? 'selected' : null;
} elseif ($selected instanceof Collection) {
return $selected->contains($value) ? 'selected' : null;
}
return ((string) $value == (string) $selected) ? 'selected' : null;
}
回答by Sagar Gautam
Usually, pluck()method gives you associative array of values
in string values.
通常，pluck()方法为您提供字符串值中的值的关联数组。
So, try using selectstatements like this:
所以，尝试使用这样的select语句：
$data = Alphabet::select('id','name')->get()->toArray();
This will give you following result:
这将为您提供以下结果：
array:3 [▼
0 => array:2 [▼
"id" => 1
"name" => "Apple"
]
1 => array:2 [▼
"id" => 2
"name" => "Ball"
]
2 => array:2 [▼
"id" => 3
"name" => "Cat"
]
]
Now, using simple loop you can get your expected array.
现在，使用简单的循环，您可以获得预期的数组。
$expected = array();
foreach($data as $d){
$expected[$d['name']] = $d['id'];
}
dd($expected);
