php Laravel - 小于/大于日期语法

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/41180569/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-08-26 02:20:53  来源:igfitidea点击:

Laravel - where less/greater than date syntax

phplaravel

提问by Selim

This is not showing the correct count. What is the correct syntax ?

这没有显示正确的计数。什么是正确的语法?

$this->data['Tasks'] = \DB::table('tb_tasks')->where('Status', 'like', 'Open%')->whereDate('DeadLine', '>', 'CURDATE()')->count();

回答by jeanj

Use a Carbon instance:

使用碳实例:

$this->data['Tasks'] = \DB::table('tb_tasks')->where('Status', 'like', 'Open%')->whereDate('DeadLine', '>', Carbon::now())->count();

回答by devplayer

Use DB::raw:

使用DB::raw

->where('datefield', '>', \DB::raw('NOW()'))

回答by Chandan Sharma

We can also try this one. It works for me.

我们也可以试试这个。这个对我有用。

    $date = "2020-04-10";

    /* 
    Assumimng DB `login_date` datetime format is "Y-m-d H:i:s"
    */

    $from_date = $date.' 00:00:01';

    ->where('login_date', '>=', $from_date);

By adding Where Clause in the query, we can find the result having rows after the particular date.

通过在查询中添加 Where 子句,我们可以找到在特定日期之后具有行的结果。