Bash 如何将 stderr 捕获到变量?

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/11087499/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-09-09 22:16:05  来源:igfitidea点击:

Bash how do you capture stderr to a variable?

bashstderr

提问by stackoverflow

Bash how do you capture stderr to a variable?

Bash 如何将 stderr 捕获到变量?

I would like to do something like this inside of my bash script

我想在我的 bash 脚本中做这样的事情

sh -c path/myExcecutable-bin 2>&1 =MYVARIABLE

How do you send stderror output to a variable ?

如何将 stderror 输出发送到变量?

回答by Tim Pote

To save both stdoutandstderrto a variable:

为了节省stdoutstderr变量:

MYVARIABLE="$(path/myExcecutable-bin 2>&1)"

Note that this interleaves stdout and stderr into the same variable.

请注意,这会将 stdout 和 stderr 交错到同一个变量中。

To save juststderrto a variable:

保存stderr到变量:

MYVARIABLE="$(path/myExcecutable-bin 2>&1 > /dev/null)"