在 bash 中使用带有 cp 的变量
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Using variable with cp in bash
提问by Todd
The file returned will have spaces in the file name so I run the file name through sed to append quotes at the beginning and end. However, when I use $CF with cp it fails. If I manually echo $CF and use the resulting file in place of $CF it works just fine. What's the problem?
返回的文件将在文件名中包含空格，因此我通过 sed 运行文件名以在开头和结尾附加引号。但是，当我将 $CF 与 cp 一起使用时，它会失败。如果我手动回显 $CF 并使用生成的文件代替 $CF 它工作得很好。有什么问题？
CF=`ls -tr /mypath/CHS1*.xlsx | tail -1 | sed -e 's/^/"/g' -e 's/$/"/g'`
cp $CF "/mydest/myfile.xlsx"
回答by Carl Norum
You don't need to add the quotes like that (in fact, it probably won't work). Instead, just use them in the cpline:
您不需要添加这样的引号（实际上，它可能不起作用）。相反，只需cp在行中使用它们：
CF=$(ls -tr /mypath/CHS1*.xlsx | tail -1)
cp "$CF" "/mydest/myfile.xlsx"
I changed it from using backticks to the newer (and preferred) $()syntax.
我将它从使用反引号更改为更新的（和首选的）$()语法。
