在 linux 终端中,如何显示文件夹的上次修改日期,同时考虑其内容?
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in linux terminal, how do I show the folder's last modification date, taking its content into consideration?
提问by Richard Rodriguez
So here's the deal. Let's say I have a directory named "web", so
所以这就是交易。假设我有一个名为“web”的目录,所以
$ ls -la
drwx------ 4 rimmer rimmer 4096 2010-11-18 06:02 web
BUT inside this directory, web/php/
但是在这个目录中,web/php/
$ ls -la
-rw-r--r-- 1 rimmer rimmer 1957 2011-01-05 08:44 index.php
That means that even though the content of my directory, /web/php/index.php has been last modified at 2011-01-05, the /web/ directory itself is reported as last modified at 2010-11-18.
这意味着即使我的目录 /web/php/index.php 的内容最后一次修改是在 2011-01-05,但 /web/ 目录本身被报告为最后一次修改是在 2010-11-18。
What I need to do is have my /web/ directory's last modification date reported as the latest modification date of any file/directory inside this directory, recursively.
我需要做的是将我的 /web/ 目录的最后修改日期报告为该目录中任何文件/目录的最新修改日期,递归。
How do I go about doing this?
我该怎么做?
采纳答案by Paulo Scardine
Something like:
就像是:
find /path/ -type f -exec stat \{} --printf="%y\n" \; |
sort -n -r |
head -n 1
Explanation:
解释:
- the find command will print modification time for every file recursively ignoring directories (according to the comment by IQAndreas you can't rely on the folders timestamps)
- sort -n (numerically) -r (reverse)
- head -n 1: get the first entry
- find 命令将递归地忽略目录打印每个文件的修改时间(根据 IQAndreas 的评论,您不能依赖文件夹时间戳)
- sort -n(数字) -r(反向)
- head -n 1:获取第一个条目
回答by Martian
If I could, I would vote for the answer by Paulo. I tested it and understood the concept. I can confirm it works.
The find
command can output many parameters.
For example, add the following to the --printf
clause:
如果可以,我会投票支持保罗的答案。我测试了它并理解了这个概念。我可以确认它有效。该find
命令可以输出很多参数。例如,在--printf
子句中添加以下内容:
%a for attributes in the octal format
%n for the file name including a complete path
Example:
例子:
find Desktop/ -exec stat \{} --printf="%y %n\n" \; | sort -n -r | head -1
2011-02-14 22:57:39.000000000 +0100 Desktop/new file
Let me raise this question as well: Does the author of this question want to solve his problem using Bash or PHP? That should be specified.
我也提出这个问题:这个问题的作者是想用Bash还是PHP来解决他的问题?这应该被指定。
回答by Paused until further notice.
If you have a version of find
(such as GNU find
) that supports -printf
then there's no need to call stat
repeatedly:
如果您有一个支持的版本find
(例如 GNU find
),-printf
则无需stat
重复调用:
find /some/dir -printf "%T+\n" | sort -nr | head -n 1
or
或者
find /some/dir -printf "%TY-%Tm-%Td %TT\n" | sort -nr | head -n 1
If you don't need recursion, though:
但是,如果您不需要递归:
stat --printf="%y\n" *