C++ 使用擦除和插入替换向量中的元素
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Replacing elements in vector using erase and insert
提问by Nikolai Stiksrud
void replace(vector<string> my_vector_2, string old, string replacement){
vector<string>::iterator it;
for (it = my_vector_2.begin(); it != my_vector_2.end(); ++it){
if (*it==old){
my_vector_2.erase(it);
my_vector_2.insert(it,replacement);
}
}
}
So, I'd like this function to replace all occurrences of the string old in the vector with the string replacement. But when calling this function, it simply doesn't change the vector at all. I'm not sure if I am using the erase and insert functions properly. Any ideas?
所以，我希望这个函数用字符串替换来替换向量中所有出现的字符串 old 。但是当调用这个函数时，它根本不会改变向量。我不确定我是否正确使用了擦除和插入功能。有任何想法吗？
回答by alexrider
At first you need to pass vector by reference, not by value.
首先你需要通过引用传递向量，而不是通过值。
void replace(vector<string>& my_vector_2, string old, string replacement){
Second erase and insert invalidatesit, you need to update it with new iterator returned by erase
第二次擦除和插入使其无效，您需要使用擦除返回的新迭代器更新它
it = my_vector_2.erase(it);
it = my_vector_2.insert(it,replacement);
回答by Kerrek SB
回答by bash.d
You are passing your std::vectoras a value. In order to Change the std::vectoryou pass to the function, declare it as a reference
你正在传递你的std::vector作为一个值。为了更改std::vector您传递给函数的内容，请将其声明为引用
void replace(vector<string>& my_vector_2, string old, string replacement){ }
The &denotes that you pass your std::vectorby reference and so you can access the object you passed.
在&表示你通过你的std::vector参考，并且这样你就可以访问你传递的对象。
And don't erase the element, simply replace it.
并且不要擦除元素，只需替换它。
