bash 如何对除 .svn 目录下的文件外的所有文件递归运行命令
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How to run a command recursively on all files except for those under .svn directories
提问by zr.
Here is how i run dos2unix recursively on all files:
这是我在所有文件上递归运行 dos2unix 的方法：
find -exec dos2unix {} \;
What do i need to change to make it skip over files under .svn/ directories?
我需要更改什么才能跳过 .svn/ 目录下的文件？
回答by Paul R
Actual tested solution:
实际测试的解决方案：
$ find . -type f \! -path \*/\.svn/\* -exec dos2unix {} \;
回答by pixelbeat
Here's a general script on which you can change the last line as required. I've taken the technique from my findreposcript:
这是一个通用脚本，您可以根据需要更改最后一行。我从我的findrepo脚本中获取了该技术：
repodirs=".git .svn CVS .hg .bzr _darcs"
for dir in $repodirs; do
repo_ign="$repo_ign${repo_ign+" -o "}-name $dir"
done
find \( -type d -a \( $repo_ign \) \) -prune -o \
\( -type f -print0 \) |
xargs -r0 \
dos2unix
回答by Tore Olsen
Just offering an additional tip: piping the result through xargs instead of using find's -exec option will increase the performance when going through a large directory structure if the filtering program accepts multiple arguments, as this will reduce the number of fork()'s, so:
只是提供一个额外的提示：如果过滤程序接受多个参数，通过 xargs 管道而不是使用 find 的 -exec 选项将提高性能，因为这将减少 fork() 的数量，所以：
find <opts> | xargs dos2unix
查找 <选项> | xargs dos2unix
One caveat: piping through xargs will fail horribly if any filenames include whitespace.
一个警告：如果任何文件名包含空格，通过 xargs 管道将严重失败。
回答by ghostdog74
find . -path ./.svn -prune -o -print0 | xargs -0 -i echo dos2unix "{}" "{}"
if you have bash 4.0
如果你有 bash 4.0
shopt -s globstar
shopt -s dotglob
for file in /path/**
do
case "$file" in
*/.svn* )continue;;
esac
echo dos2unix $file $file
done
回答by yogsototh
In bash
在 bash 中
for fic in **/*; dos2unix $fic
Or even better in zsh
甚至在 zsh 中更好
for fic in **/*(.); dos2unix $fic
