laravel 如何在laravel中将当前网址分享到facebook？
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how to share the current url to facebook in laravel?
提问by Naveen Kumar
I want to share the current URL of my website to the facebook , so i used facebook's sharer.php. Here is my share.php file which shows icons and link to the sharer.php
我想将我网站的当前 URL 分享到 facebook，所以我使用了 facebook 的 sharer.php。这是我的 share.php 文件，它显示了图标和指向 sharer.php 的链接
<div class="social-buttons">
<a href="https://www.facebook.com/sharer/sharer.php?u={{ urlencode($url) }}"
target="_blank">
<i class="fa fa-facebook-official"></i>
</a>
</div>
I am passing the url to the ($url) from my page through the code
我正在通过代码将 url 从我的页面传递到 ($url)
<?php
use App\Http\Requests;
use Illuminate\Http\Request;
?>
@include('share',['url' => 'www.google.com'])
This particular webpage i am sharing the URL from usually generate dynamic URL. So I change the code to
我共享的这个特定网页的 URL 通常会生成动态 URL。所以我把代码改成
@include('share',['url' => 'Request::url()'])
so that i can share the dynamically created URL. The problem here is When i put www.google.comin place of url the POP UP box works fine and open up the facebook share. But when i use ['url' => 'Request::url()'])the pop up box opens and close quickly , i tried to see the url and it was something like error. How do i fix this? is there any drawback in this approach ?
这样我就可以共享动态创建的 URL。这里的问题是当我www.google.com代替 url 时，POP UP 框工作正常并打开 facebook 共享。但是当我使用['url' => 'Request::url()'])弹出框快速打开和关闭时，我试图查看 url 并且它是类似错误的东西。我该如何解决？这种方法有什么缺点吗？
Here is the script code
这是脚本代码
<script src="https://code.jquery.com/jquery-2.2.0.min.js"></script>
<script>
var popupSize = {
width: 780,
height: 550
};
$(document).on('click', '.social-buttons > a', function(e){
var
verticalPos = Math.floor(($(window).width() - popupSize.width) / 2),
horisontalPos = Math.floor(($(window).height() - popupSize.height) / 2);
var popup = window.open($(this).prop('href'), 'social',
'width='+popupSize.width+',height='+popupSize.height+
',left='+verticalPos+',top='+horisontalPos+
',location=0,menubar=0,toolbar=0,status=0,scrollbars=1,resizable=1');
if (popup) {
popup.focus();
e.preventDefault();
}
});
</script>
回答by jedrzej.kurylo
When you do
当你做
@include('share',['url' => 'Request::url()'])
you're passing a string Request::url()as the value, not the URL.
您传递的是字符串Request::url()作为值，而不是 URL。
Replace that line with:
将该行替换为：
@include('share',['url' => Request::url()])
