Python 将输入（来自标准输入）转换为列表
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Converting input (from stdin) into lists
提问by Noob Coder
I need to convert input(series of integers) into a bunch of lists.
我需要将输入（整数系列）转换为一堆列表。
Sample Input:
样本输入：
3
2
2 2 4 5 7
Sample Output:
示例输出：
list1=[3]
list2=[2]
list3=[2,2,4,5,7]
I am trying to do this:
我正在尝试这样做：
list=[]
import sys
for line in sys.stdin:
list.append(line)
but print list returns
但打印列表返回
['3\n', '2\n', '2 2 4 5 7']
采纳答案by juliomalegria
Use splitto split a string into a list, for example:
使用split一个字符串分割成一个列表，例如：
>>> '2 2 4 5 7'.split()
['2', '2', '4', '5', '7']
As you see, elements are string. If you want to have elements as integers, use intand a list comprehension:
如您所见，元素是字符串。如果要将元素作为整数，请使用int和列表理解：
>>> [int(elem) for elem in '2 2 4 5 7'.split()]
[2, 2, 4, 5, 7]
So, in your case, you would do something like:
因此，在您的情况下，您会执行以下操作：
import sys
list_of_lists = []
for line in sys.stdin:
new_list = [int(elem) for elem in line.split()]
list_of_lists.append(new_list)
You will end up having a list of lists:
您最终将得到一个列表列表：
>>> list_of_lists
[[3], [2], [2, 2, 4, 5, 7]]
If you want to have those lists as variables, simply do:
如果您想将这些列表作为变量，只需执行以下操作：
list1 = list_of_lists[0] # first list of this list of lists
list1 = list_of_lists[1] # second list of this list of lists
list1 = list_of_lists[2] # an so on ...
回答by óscar López
Here's one way:
这是一种方法：
import ast
line = '1 2 3 4 5'
list(ast.literal_eval(','.join(line.split())))
=> [1, 2, 3, 4, 5]
The idea is, that for each line you read you can turn it into a list using literal_eval(). Another, shorter option would be to use list comprehensions:
这个想法是，对于您阅读的每一行，您都可以使用literal_eval(). 另一个更短的选择是使用列表推导式：
[int(x) for x in line.split()]
=> [1, 2, 3, 4, 5]
The above assumes that the numbers are integers, replace int()with float()in case that the numbers have decimals.
上面假设数字是整数，如果数字有小数，请替换int()为float()。
