echo bash 变量作为文本
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echo bash variable as text
提问by alexj
I am trying to echo a var as text and not parse it. Everything I have tried and searched for just seems to show me how to echo the variable and not the variable text only.
我试图将 var 作为文本回显而不是解析它。我尝试和搜索的所有内容似乎都在向我展示如何回显变量，而不仅仅是变量文本。
Note the code below is just what I have as basic echo. I have tried \"$ARG1$\" etc with this line.
请注意，下面的代码正是我所拥有的基本回声。我已经用这条线尝试过 \"$ARG1$\" 等。
echo "command[runcmd]=sudo service $ARG1$ restart" >> testfile
What I want is for it to show
我想要的是让它显示
command[runcmd]=sudo service $ARG1$ restart
BUT what it ends up as is
但结果是这样
command[runcmd]=sudo service $ restart
I know this is a syntax error on my part but I can't seem to find the proper way even in the in MAN pages. Maybe I am missing something.
我知道这是我的语法错误，但即使在 MAN 页面中我似乎也找不到正确的方法。也许我错过了一些东西。
Thank you in advance!
先感谢您！
回答by glenn Hymanman
Just use single quotes: they prevent variable substitution:
只需使用单引号：它们可以防止变量替换：
echo 'command[runcmd]=sudo service $ARG1$ restart'
回答by Paul Evans
Use single quotes (') instead of double ("):
使用单引号 (') 而不是双引号 (")：
echo 'command[runcmd]=sudo service $ARG1$ restart' >> testfile
