bash 如何在 Makefile 中使用 sed
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How to use sed in a Makefile
提问by Tom
I have tried putting the following in my Makefile:
我尝试将以下内容放入我的 Makefile 中：
@if [ $(DEMO) -eq 0 ]; then \
cat sys.conf | sed -e "s#^public_demo[\s=].*$#public_demo=0#" >sys.conf.temp; \
else \
cat sys.conf | sed -e "s#^public_demo[\s=].*$#public_demo=1#" >sys.conf.temp; \
fi
but when I run make, I get the following error:
但是当我运行make 时，出现以下错误：
sed: -e expression #1, char 30: unterminated `s' command
If I run the exact lines that contain sedin the console, they behave correctly.
如果我运行sed控制台中包含的确切行，它们的行为是正确的。
Why am I getting this error and how can the problem be fixed?
为什么我会收到此错误以及如何解决问题？
回答by Erik Edin
It might be the $ sign in the substitution that is interpreted by make as a variable. Try using two of them like .*$$#public_demo. Then make will expand that to a single $.
可能是替换中的 $ 符号被 make 解释为变量。尝试使用其中的两个，例如.*$$#public_demo。然后 make 将其扩展为单个 $。
EDIT: This was only half the answer. As cristis answered: the other part is that one needs to use single quotes to prevent bash from expanding the $ sign too.
编辑：这只是答案的一半。正如克里斯蒂斯回答的那样：另一部分是需要使用单引号来防止 bash 也扩展 $ 符号。
回答by cristis
I suggest you use single quotes instead of double quotes, the $might be processed as a special char by make before running sed:
我建议您使用单引号而不是双引号，$在运行 sed 之前，make 可能会将其作为特殊字符处理：
cat sys.conf | sed -e 's#^public_demo[\s=].*$#public_demo=0#' >sys.conf.temp;
回答by jiych.guru
The makeversion in my machine is:
make我机器上的版本是：
$ make --version
GNU Make 3.81
Copyright (C) 2006 Free Software Foundation, Inc.
This is free software; see the source for copying conditions.
There is NO warranty; not even for MERCHANTABILITY or FITNESS FOR A
PARTICULAR PURPOSE.
This program built for x86_64-redhat-linux-gnu
And the sedversion:
和sed版本：
$ sed --version
GNU sed version 4.2.1
I must add backslash for $to prevent sed taking it as end of line:
我必须添加反斜杠 for$以防止 sed 将其作为行尾：
cat sys.conf | sed -e 's#^public_demo[\s=].*$$#public_demo=0#' >sys.conf.temp
回答by rubo77
I tried double $$sign but it didn't work in my problem, maybe $$$$or $$$$$$$$would have worked, because my Makefile calls other Makefiles and so on. But I found a better solution:
我尝试了双重$$签名，但它在我的问题中不起作用，也许$$$$或$$$$$$$$本来可以工作，因为我的 Makefile 调用了其他 Makefile 等等。但我找到了一个更好的解决方案：
Create a shell file replacer.shin the same folder as your Makefile that executes the sedcommand. Give it executable bit with
replacer.sh在与执行sed命令的Makefile 相同的文件夹中创建一个 shell 文件。给它可执行位
chmod +x replacer.sh
Now you can call this file in your Makefile:
现在你可以在你的 Makefile 中调用这个文件：
./replacer.sh
回答by jcomeau_ictx
one problem I had with using sed in a makefile isn't addressed by the current answers, so I'll explain it here. I was populating Bash variables like so: remote_owner=$$($(MAKE) remote.owner)and then using those variables in my sed substitution. problem is, due to the convoluted way my rules are set up, remote_ownercould have make's own output in it, giving me the error:
我在 makefile 中使用 sed 时遇到的一个问题目前的答案没有解决，所以我将在这里解释。我像这样填充 Bash 变量：remote_owner=$$($(MAKE) remote.owner)然后在我的 sed 替换中使用这些变量。问题是，由于我的规则设置方式复杂，remote_owner可能会有自己的输出，给我错误：
sed: -e expression #1, char 69: unknown option to `s'
make: *** [alter_table_local.sql] Error 1
for example, by adding debugging messages, I found local_owner set to:
例如，通过添加调试消息，我发现 local_owner 设置为：
make[1]: Entering directory `/home/jcomeau/rentacoder/jh'
jcomeau
the answer was to add the --silentoption to make: remote_owner=$$($(MAKE) --silent remote.owner)
答案是添加以下--silent选项：remote_owner=$$($(MAKE) --silent remote.owner)
回答by Sjoerd
Use something else than #to separate parts.
使用其他东西而不是#分开零件。
