如何将日期格式 d/m/Y 更改为 Ymd PHP
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How to change date format d/m/Y to Y-m-d PHP
提问by user3099298
I want to keep date format d/m/Y (24/12/2013) in client side (users enter date in that format from JQuery date picker). But in server side I convert it to Y-m-d(2013-12-24) format.
我想在客户端保留日期格式 d/m/Y (24/12/2013)（用户从 JQuery 日期选择器输入该格式的日期）。但在服务器端，我将其转换为 Ymd(2013-12-24) 格式。
To do that I wrote code in this way
为此，我以这种方式编写了代码
$brithdate = explode('/', $_POST['brithday']);
$brithdateFormated = $brithdate[2] . "-" . $brithdate[1] . "-" . $brithdate[0];
Is this correct? or is there any easy way to do that
这样对吗？或者有什么简单的方法可以做到这一点
回答by Amal Murali
Use DateTime objects when you're working with dates and times. You can use DateTime::createFromFormat()to parse the date string and then the DateTime::format()to format it the way you want:
在处理日期和时间时使用 DateTime 对象。您可以使用 DateTime::createFromFormat()解析日期字符串，然后DateTime::format()按照您想要的方式对其进行格式化：
$str = '24/12/2013';
$date = DateTime::createFromFormat('d/m/Y', $str);
echo $date->format('Y-m-d'); // => 2013-12-24
For a list of available formatting options, see the documentation.
有关可用格式选项的列表，请参阅文档。
回答by Rizwan Sultan
Try this
尝试这个
$birthdate= strtotime($_POST['brithday']);
$brithdateFormated = date("d/m/Y",$birthdate);
回答by Parth Patel
This is working for me.
这对我有用。
$start_date='04/05/2018';
$convertedDate= DateTime::createFromFormat('d/m/Y', $start_date)->format('Y-m-d');
Note: The First parameter should be same as your $start_date with '/' also. If you put '-' there, then it will not perform the correct conversion.
注意：第一个参数也应该与您的 $start_date 相同，并带有“/”。如果你把'-'放在那里，那么它不会执行正确的转换。
