Java 如何正确显示纳米时间到秒的转换
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how correctly display nanotime to second conversion
提问by chris edwards
I have a BFS algorithm to solve the 8-Puzzle, and one of the project requirements is to output the amount of time it takes to find the shallowest solution.
我有一个BFS算法来解决8-Puzzle，项目需求之一是输出找到最浅解所花费的时间。
I am using System.nanoTime()to keep track of the applications run time because it solves the majority of the given puzzles in well under a second.
我System.nanoTime()用来跟踪应用程序的运行时间，因为它在一秒钟内解决了大多数给定的难题。
The problem i am having is whem i convert my nanoTimeto seconds, it displays in a weird format.
我遇到的问题是我将我转换nanoTime为秒，它以奇怪的格式显示。
the following code is used:
使用以下代码：
final long startTime = System.nanoTime();
//algorithm code removed for simplicity this all functions correctly
final long duration = System.nanoTime() - startTime;
final double seconds = ((double)duration / 1000000000);
System.out.println("Nano time total: " + duration);
System.out.println("solution Time : " + seconds + " Seconds");
This produces the output:
这会产生输出：
Nano time total: 916110
solution time : 9.1611E-4 Seconds
I have also tried using floats to represent the values.
我也尝试过使用浮点数来表示值。
is anybody able to provide a better way to convert/display, maybe use a format output statement?
有没有人能够提供更好的转换/显示方式，也许使用格式输出语句？
Thanks for taking the time to read my question.
感谢您花时间阅读我的问题。
采纳答案by akasha
I think you need: DecimalFormat
我认为你需要：DecimalFormat
System.out.println("solution Time : " + new DecimalFormat("#.##########").format(seconds) + " Seconds");
回答by Amadan
System.out.format("solution Time : %f Seconds", seconds);
for the classic, non-exponential floating point number.
对于经典的非指数浮点数。
