在 Ruby 中删除数组中的 nil 和空白字符串
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Remove nil and blank string in an array in Ruby
提问by Cary Swoveland
I am new to Ruby and stuck with this issue. Let's say I have an array like this:
我是 Ruby 的新手并且一直在解决这个问题。假设我有一个这样的数组：
arr = [1, 2, 's', nil, '', 'd']
and I want to remove nil and blank string from it, i.e. final array should be:
我想从中删除 nil 和空白字符串，即最终数组应该是：
arr = [1, 2, 's', 'd']
I tried compactbut it gives this:
我试过了，compact但它给出了这个：
arr.compact!
arr #=> [1, 2, 's', '', 'd'] doesn't remove empty string.
I was wondering if there's a smart way of doing this in Ruby.
我想知道在 Ruby 中是否有一种聪明的方法来做到这一点。
回答by Cary Swoveland
You could do this:
你可以这样做：
arr.reject { |e| e.to_s.empty? } #=> [1, 2, "s", "d"]
Note nil.to_s => ''.
注意nil.to_s => ''。
回答by awendt
Since you want to remove both niland empty strings, it's not a duplicate of How do I remove blank elements from an array?
由于您要同时删除nil和空字符串，因此它不是如何从数组中删除空白元素的副本？
You want to use .reject:
你想使用.reject：
arr = [1, 2, 's', nil, '', 'd']
arr.reject { |item| item.nil? || item == '' }
NOTE:rejectwith and without bang behaves the same way as compactwith and without bang: reject!and compact!modify the array itself while rejectand compactreturn a copy of the array and leave the original intact.
注意：reject有和没有爆炸的行为方式相同，compact有和没有爆炸：reject!和compact!修改数组本身，而reject与compact返回数组的副本，并保留原始不变。
If you're using Rails, you can also use blank?. It was specifically designed to work on nil, so the method call becomes:
如果你使用 Rails，你也可以使用blank?. 它专门设计用于处理nil，因此方法调用变为：
arr.reject { |item| item.blank? }
回答by JayJay
I tend to do:
我倾向于这样做：
arr = [1, 2, 's', nil, '', 'd']
arr.reject(&:blank?)
returns:
返回：
=> [1, 2, "s", "d"]
回答by Manindra Gautam
arr.reject(&:blank?)
arr.reject(&:blank?)
Just use this, no need to anything else.
就用这个，不需要别的。
回答by potashin
You can also use -to remove all niland ''elements:
您还可以使用-删除所有nil和''元素：
arr -= [nil, '']
#=> [1, 2, "s", "d"]
Or compactand rejectwith shortcut (in case you are not using Rails where you can just use arr.reject(&:blank?)):
或者compact和reject与快捷方式（如果你不使用Rails，你可以只使用arr.reject(&:blank?)）：
arr = arr.compact.reject(&''.method(:==))
#=> [1, 2, "s", "d"]
回答by RockStar
You can use compact with reject
您可以将 compact 与拒绝一起使用
arr = [1, 2, 's', nil, '', 'd']
arr = [1, 2, 's', 'd']
arr = arr.compact.reject { |h| h == "" }
or
或者
arr = arr.compact.delete_if { |h| h == "" }
回答by Jigar Panchal
The simplest and fast way of doing this is :
最简单快速的方法是：
arr = [1, 2, 's', nil, '', 'd'] - [nil,'']
==> arr = [1, 2, 's', 'd']
回答by padmapriya
You can use compact and delete_if method to remove nil and blank string in an array in Ruby
您可以使用 compact 和 delete_if 方法在 Ruby 中删除数组中的 nil 和空白字符串
arr = [1, 2, 's', nil, '', 'd']
arr.compact!.delete_if{|arrVal| arrVal.class == String and arrVal.empty?}
=> [1, 2, "s", "d"]
回答by Varun Gupta
Hope this will work for your case :
希望这对您的情况有用：
arr = [1, 2, 's', nil, '', 'd']
arr.select{|x| x.to_s!="" }
回答by Dom
I would probably add .stripto eliminate potential whitespace headaches (assuming its not a rails app).
我可能会添加.strip以消除潜在的空白问题（假设它不是 Rails 应用程序）。
array = [1, 2, "s", nil, " ", "d", "\n"]
array.reject!{|a| a.nil? || (a.to_s.strip.empty?) }
#=> [1, 2, "s", "d"]
