Python pickle/unpickle 列表到/从文件
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Python pickle/unpickle a list to/from a file
提问by atomh33ls
I have a list that looks like this:
我有一个看起来像这样的列表：
a = [['a string', [0, 0, 0], [22, 'bee sting']], ['see string',
[0, 2, 0], [22, 'd string']]]
and am having problems saving it and retrieving it.
并且在保存和检索它时遇到问题。
I can save it ok using pickle:
我可以使用pickle保存它：
with open('afile','w') as f:
pickle.dump(a,f)
but get the following error when I try to load it:
但是当我尝试加载它时出现以下错误：
pickle.load('afile')
Traceback (most recent call last):
File "<pyshell#116>", line 1, in <module>
pickle.load('afile')
File "C:\Python27\lib\pickle.py", line 1378, in load
return Unpickler(file).load()
File "C:\Python27\lib\pickle.py", line 841, in __init__
self.readline = file.readline
AttributeError: 'str' object has no attribute 'readline'
I had thought that I could convert to a numpy array and use save, savezor savetxt. However I get the following error:
我原以为我可以转换为一个 numpy 数组并使用save,savez或savetxt. 但是我收到以下错误：
>>> np.array([a])
Traceback (most recent call last):
File "<pyshell#122>", line 1, in <module>
np.array([a])
ValueError: cannot set an array element with a sequence
采纳答案by Rapolas K.
Decided to make it as an answer. pickle.load method expects to get a file like object, but you are providing a string instead, and therefore an exception. So instead of:
决定把它作为答案。pickle.load 方法期望获得一个类似对象的文件，但您提供的是一个字符串，因此是一个例外。所以而不是：
pickle.load('afile')
you should do:
你应该做：
pickle.load(open('afile', 'rb'))
回答by atomh33ls
To add to @ Rapolas K's answer:
添加到@ Rapolas K 的回答中：
I found that I had problems with the file not closing so used this method:
我发现我的文件没有关闭有问题所以使用了这个方法：
with open('afile','rb') as f:
pickle.load(f)
