java android上的Ksoap--从Java Web服务获取列表响应
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/4416798/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Ksoap on android-- get a list response from a java web service
提问by Hamzus
I have a java web service (soap) which i want to use with an android client for that am using ksoap.
我有一个 Java Web 服务（soap），我想将它与一个使用 ksoap 的 android 客户端一起使用。
My web service gives an answer which look like this :
我的网络服务给出了如下所示的答案：
<S:Envelope xmlns:S="http://schemas.xmlsoap.org/soap/envelope/">
<S:Body>
<ns2:listealbumResponse xmlns:ns2="http://ws/">
<return xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="ns2:album">
<annee>2008</annee>
<id>6</id>
<titre>Ninja Tuna</titre>
</return>
<return xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="ns2:album">
<annee>2008</annee>
<id>10</id>
<titre>Fine Music, Vol. 1</titre>
</return>
<return xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="ns2:album">
<annee>2004</annee>
<id>14</id>
<titre>Bob Acri</titre>
</return>
<return xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="ns2:album">
<annee>2009</annee>
<id>54</id>
<titre>Rated R</titre>
</return>
</ns2:listealbumResponse>
</S:Body>
</S:Envelope>
wich is a list of object
这是一个对象列表
To call my web service i use this code :
要调用我的网络服务，我使用以下代码：
try{
SoapObject Request = new SoapObject(NAMESPACE, METHOD_NAME);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = false;
envelope.setOutputSoapObject(Request);
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
androidHttpTransport.call(SOAP_ACTION, envelope);
SoapObject result = (SoapObject)envelope.getResponse();
When i tested my response "result" it's got only one object , how could i get all the list and parse it?
当我测试我的响应“结果”时，它只有一个对象，我如何获取所有列表并解析它？
回答by Hamzus
The problem was that when i parse the soap response i got only the first object of the list so i changer this line :
问题是，当我解析肥皂响应时，我只得到了列表的第一个对象，所以我更改了这一行：
SoapObject result = (SoapObject)envelope.getResponse();
with :
和 ：
SoapObject result = (SoapObject)envelope.bodyIn;
wiht that i got all the list and i add this
有了所有列表，我添加了这个
testValues = new String[result.getPropertyCount()];
for(int i= 0; i< result.getPropertyCount(); i++){
testValues[i] = result.getProperty(i).toString();
}
Good luck and thank you Janusz
祝你好运，谢谢你 Janusz
回答by maxy
Code:
代码：
SoapObject result = (SoapObject)envelope.bodyIn;
String output = "";
for(int i= 0; i< result.getPropertyCount(); i++){
SoapObject object = (SoapObject)response.getProperty(i);
output += "annee : " + object.getProperty("annee") + "\n";
output += "id : " + object.getProperty("id") + "\n";
output += "titre : " + object.getProperty("titre") + "\n";
}
回答by Janusz
The result is a single SoapObjectthis objects however should have a property for every item in the list that you requested. You could do something like this to retrieve all the items:
结果是一个SoapObject这个对象但是应该为您请求的列表中的每个项目具有一个属性。您可以执行以下操作来检索所有项目：
private static List parseLists(List listItems, SoapObject response) {
int propertyCount = response.getPropertyCount();
for (int currentProperty = 0; currentProperty < propertyCount; currentProperty++) {
Object input = response.getProperty(currentProperty);
Object result = parseObject(input.toString());
if (result != null) {
listItems.add(result);
}
}
return listItems;
}
