如何在 Bash 中进行浮动比较？
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时间：2020-09-09 22:26:52 来源:igfitidea点击:
How to do float comparison in Bash?
提问by igustin
lock_percent=$(echo "scale = 5; $value2*100/$value1" | bc)
value=`echo "$lock_percent" | bc`
if [[ "$value" > "" ]]; then
echo "Lock Percentage:$value percentage State Critical"
exit $STATE_CRITICAL
fi
I am not able to perform a float comparison with this. I am not able to understand where I am going wrong.
我无法对此进行浮点比较。我无法理解我哪里出错了。
回答by igustin
Bash itself can't use float. In this case maybe you can multiply by 10 or 100 (etc.) and get integer value which you can compare. Or, you can use bccomparison and return value:
Bash 本身不能使用浮动。在这种情况下，也许您可以乘以 10 或 100（等）并获得可以比较的整数值。或者，您可以使用bc比较和返回值：
echo "10.2>10.1" | bc
回答by slitvinov
# float number comparison
fcomp() {
awk -v n1="" -v n2="" 'BEGIN {if (n1+0<n2+0) exit 0; exit 1}'
}
# test and example
fcomp_test() {
if fcomp "" ""; then
echo "<"
else
echo ">="
fi
}
fcomp_test 0.0 0.1
fcomp_test 0.1 0.1
fcomp_test -0.1 0.1
fcomp_test 1e3 1e4
fcomp_test -1.34e3 1.03e4
fcomp_test ' 0 ' ' 1 '
