从 Python 中的列表中删除多个项目
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Remove multiple items from list in Python
提问by mid_kid
So, for example, I got a list: myList=["asdf","ghjk","qwer","tyui"]
I also have a list of index numbers of the items I want to remove: removeIndexList=[1,3](I want to remove items 1 and 3 from the list above)
因此，例如，我有一个列表：myList=["asdf","ghjk","qwer","tyui"]
我还有一个要删除的项目的索引号列表：（removeIndexList=[1,3]我想从上面的列表中删除项目 1 和 3）
What would be the best way to do this?
什么是最好的方法来做到这一点？
采纳答案by Martijn Pieters
Use a list comprehension with enumerate():
使用列表理解enumerate()：
newlist = [v for i, v in enumerate(oldlist) if i not in removelist]
making removelista setinstead will help speed things along:
制作removelist一个set代替将有助于加快速度：
removeset = set(removelist)
newlist = [v for i, v in enumerate(oldlist) if i not in removeset]
Demo:
演示：
>>> oldlist = ["asdf", "ghjk", "qwer", "tyui"]
>>> removeset = set([1, 3])
>>> [v for i, v in enumerate(oldlist) if i not in removeset]
['asdf', 'qwer']
回答by abarnert
The obvious way will not work:
显而易见的方法是行不通的：
list=["asdf","ghjk","qwer","tyui"]
removelist=[1,3]
for index in removelist:
del list[index]
The problem is that after you've deleted #1, "ghjk", everything after that gets shifted forward. So #3 is no longer "tyui", it's past the end of the list.
问题是，在您删除 #1"ghjk" 之后，之后的所有内容都会向前移动。所以#3 不再是“tyui”，它已经超出了列表的末尾。
You can solve this by making sure you walk backward:
您可以通过确保向后走来解决此问题：
list=["asdf","ghjk","qwer","tyui"]
removelist=[1,3]
for index in sorted(removelist, reverse=True):
del list[index]
However, it's generally better to just build a new filtered list instead, as suggested by Martijn Pieters:
但是，正如 Martijn Pieters 所建议的那样，通常最好只构建一个新的过滤列表：
list = [v for i, v in enumerate(list) if i not in removelist]
