使用 SOH 分隔符在 bash 中拆分一行文本
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Split a line of text in bash using SOH delimiter
提问by syker
How do I split a line of text in bash using SOH delimiter?
如何使用 SOH 分隔符在 bash 中拆分一行文本？
回答by ghostdog74
you can use the octal value of SOH as a delimiter using awk.
您可以使用 awk 将 SOH 的八进制值用作分隔符。
$ awk -F"IFS=`echo -e ''`
1" '{print }' file
回答by Andy Mortimer
You can set the IFS variable to change the delimiter between words. (Don't forget to save the old value so you can restore it when you're done.)
您可以设置 IFS 变量来更改单词之间的分隔符。（不要忘记保存旧值，以便在完成后恢复它。）
Based on a quick google I assume "SOH delimiter" is the character with code 1, so you need to get that odd character into IFS:
基于一个快速的谷歌，我假设“SOH 分隔符”是代码为 1 的字符，因此您需要将该奇数字符放入 IFS：
##代码##If that's not enough, you probably need to expand on "split a line of text". What do you want to split it into?
如果这还不够，您可能需要扩展“拆分一行文本”。你想把它分成什么？
