删除括号之间的文本 PHP
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Remove Text Between Parentheses PHP
提问by Belgin Fish
I'm just wondering how I could remove the text between a set of parentheses and the parentheses themselves in php.
我只是想知道如何在 php.ini 中删除一组括号和括号之间的文本。
Example :
例子 ：
ABC (Test1)
ABC（测试1）
I would like it to delete (Test1) and only leave ABC
我希望它删除（Test1）并且只留下ABC
Thanks
谢谢
回答by cmptrgeekken
$string = "ABC (Test1)";
echo preg_replace("/\([^)]+\)/","",$string); // 'ABC '
preg_replaceis a perl-based regular expression replace routine. What this script does is matches all occurrences of a opening parenthesis, followed by any number of characters nota closing parenthesis, and again followed by a closing parenthesis, and then deletes them:
preg_replace是一个基于 perl 的正则表达式替换例程。该脚本的作用是匹配所有出现的左括号，后跟任意数量的字符而不是右括号，再后跟右括号，然后删除它们：
Regular expression breakdown:
正则表达式分解：
/ - opening delimiter (necessary for regular expressions, can be any character that doesn't appear in the regular expression
\( - Match an opening parenthesis
[^)]+ - Match 1 or more character that is not a closing parenthesis
\) - Match a closing parenthesis
/ - Closing delimiter
回答by Tegan Snyder
The accepted answer works great for non-nested parentheses. A slight modification to the regex allows it to work on nested parentheses.
接受的答案适用于非嵌套括号。对正则表达式稍作修改就可以处理嵌套的括号。
$string = "ABC (Test1(even deeper) yes (this (works) too)) outside (((ins)id)e)";
echo preg_replace("/\(([^()]*+|(?R))*\)/","", $string);
回答by tyjkenn
$string = "ABC (Test1(even deeper) yes (this (works) too)) outside (((ins)id)e)";
$paren_num = 0;
$new_string = '';
foreach($string as $char) {
if ($char == '(') $paren_num++;
else if ($char == ')') $paren_num--;
else if ($paren_num == 0) $new_string .= $char;
}
$new_string = trim($new_string);
It works by looping through each character, counting parentheses. Only when $paren_num == 0(when it is outside all parentheses) does it append the characters to our resulting string, $new_string.
它的工作原理是遍历每个字符，计算括号。只有当$paren_num == 0（当它在所有括号之外时）它才会将字符附加到我们的结果字符串$new_string.
回答by ghostdog74
without regex
没有正则表达式
$string="ABC (test)"
$s=explode("(",$string);
print trim($s[0]);
回答by Alex Weinstein
Folks, regular expressions CANNOT be used to parse non-regular languages. Non-regular languages are those that require state to interpret (i.e. remembering how many parenthesis are currently open).
伙计们，正则表达式不能用于解析非正则语言。非常规语言是那些需要状态来解释的语言（即记住当前打开的括号数量）。
All of the above answers will fail on this string: "ABC (hello (world) how are you)".
以上所有答案都将在此字符串上失败：“ABC (hello (world) how are you)”。
Read Jeff Atwood's Parsing Html The Cthulhu Way: https://blog.codinghorror.com/parsing-html-the-cthulhu-way/, and then use either a by-hand written parser (loop through the characters in the string, see if the character is a parenthesis or not, maintain a stack) or use a lexer/parser capable of parsing a context-free language.
阅读 Jeff Atwood 的 Parsing Html The Cthulhu Way: https://blog.codinghorror.com/parsing-html-the-cthulhu-way/，然后使用手工编写的解析器（循环遍历字符串中的字符，请参阅如果字符是否为括号，则维护堆栈）或使用能够解析上下文无关语言的词法分析器/解析器。
Also see this wikipedia article on the "language of properly matched parenthesis:" https://en.wikipedia.org/wiki/Dyck_language
另请参阅有关“正确匹配括号的语言”的维基百科文章：https: //en.wikipedia.org/wiki/Dyck_language
回答by MERT DO?AN
Most quik method (without preg):
大多数 quik 方法（不带 preg）：
$str='ABC (TEST)';
echo trim(substr($str,0,strpos($str,'(')));
If you don't want to trim spaces at end of word, just remove trim function from code.
如果您不想在词尾修剪空格，只需从代码中删除修剪功能。
回答by Naga
$str ="ABC (Test1)";
echo preg_replace( '~\(.*\)~' , "", $str );
