从python中的命令行参数获取文件路径
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getting file path from command line argument in python
提问by
Can anyone guide me how can I get file path if we pass file from command line argument and extract file also. In case we also need to check if the file exist into particular directory
如果我们从命令行参数传递文件并提取文件，任何人都可以指导我如何获取文件路径。如果我们还需要检查文件是否存在于特定目录中
python.py /home/abhishek/test.txt
get file path and check test.txt exist into abhishek folder.
获取文件路径并检查 test.txt 是否存在于 abhishek 文件夹中。
I know it may be very easy but I am bit new to pytho
我知道这可能很容易，但我对 pytho 有点陌生
回答by eumiro
import os
import sys
fn = sys.argv[1]
if os.path.exists(fn):
print os.path.basename(fn)
# file exists
回答by ATOzTOA
Use this:
用这个：
import sys
import os
path = sys.argv[1]
# Check if path exits
if os.path.exists(path):
print "File exist"
# Get filename
print "filename : " + path.split("/")[-1]
回答by Ph03n1x
I think the most elegant way is to use the ArgumentParserThis way you even get the -hoption that helps the user to figure out how to pass the arguments. I have also included an optional argument (--outputDirectory).
我认为最优雅的方法是使用ArgumentParserThis way 你甚至可以获得-h帮助用户弄清楚如何传递参数的选项。我还包含了一个可选参数 ( --outputDirectory)。
Now you can simply execute with python3 test.py /home/test.txt --outputDirectory /home/testDir/
现在你可以简单地执行 python3 test.py /home/test.txt --outputDirectory /home/testDir/
import argparse
import sys
import os
def create_arg_parser():
""""Creates and returns the ArgumentParser object."""
parser = argparse.ArgumentParser(description='Description of your app.')
parser.add_argument('inputDirectory',
help='Path to the input directory.')
parser.add_argument('--outputDirectory',
help='Path to the output that contains the resumes.')
return parser
if __name__ == "__main__":
arg_parser = create_arg_parser()
parsed_args = arg_parser.parse_args(sys.argv[1:])
if os.path.exists(parsed_args.inputDirectory):
print("File exist")
回答by nijm
Starting with python 3.4 you can use argparsetogether with pathlib:
从 python 3.4 开始，您可以将argparse与pathlib一起使用：
import argparse
from pathlib import Path
parser = argparse.ArgumentParser()
parser.add_argument("file_path", type=Path)
p = parser.parse_args()
print(p.file_path, type(p.file_path), p.file_path.exists())
