bash 在bash中将一个字符串切成几行
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cutting a string into several lines in bash
提问by SIMEL
I want to take the path of the local directory and put each directory on the path in a different line. I've tried to do it using cut:
我想取本地目录的路径并将每个目录放在不同行的路径上。我尝试使用 cut 来做到这一点：
pwd | cut -f 1- -d\/ --output-delimiter=\n
pwd | cut -f 1- -d\/ --output-delimiter=\n
but it doesn't change the '/'s into EOL, but puts n's instead. What am I doing wrong?
但它不会将 '/' 更改为 EOL，而是将 n 改为。我究竟做错了什么？
回答by aioobe
This should do the trick
这应该可以解决问题
pwd | tr '/' '\n'
If you don't want an empty line in the beginning (due to the initial /) you could do
如果你不想在开头有一个空行（由于初始/），你可以这样做
pwd | cut -b2- | tr '/' '\n'
Example:
例子：
#aioobe@r60:~/tmp/files$ pwd
/home/aioobe/tmp/files
#aioobe@r60:~/tmp/files$ pwd | cut -b2- | tr '/' '\n'
home
aioobe
tmp
files
回答by codaddict
You can try:
你可以试试：
pwd | tr '/' '\n'
回答by Paused until further notice.
This is how you would accomplish what you set out to do (using ANSI-C quoting):
这就是您将如何完成您打算做的事情（使用 ANSI-C 引用）：
pwd | cut -f 1- -d\/ --output-delimiter=$'\n'
