Python 给定点顶点如何创建多边形？
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How to create a Polygon given its Point vertices?
提问by Sounak
I want to create a polygon from shapely points.
我想从匀称的点创建一个多边形。
from shapely import geometry
p1 = geometry.Point(0,0)
p2 = geometry.Point(1,0)
p3 = geometry.Point(1,1)
p4 = geometry.Point(0,1)
pointList = [p1, p2, p3, p4, p1]
poly = geometry.Polygon(pointList)
gives me an type error TypeError: object of type 'Point' has no len()
给我一个类型错误 TypeError: object of type 'Point' has no len()
How to create a Polygonfrom shapely Pointobjects?
如何Polygon从匀称的Point对象创建一个？
采纳答案by songololo
If you specifically want to construct your Polygon from the shapely geometry Points, then call their x, y properties in a list comprehension. In other words:
如果您特别想从匀称的几何点构建多边形，请在列表推导式中调用它们的 x、y 属性。换句话说：
from shapely import geometry
poly = geometry.Polygon([[p.x, p.y] for p in pointList])
print(poly.wkt) # prints: 'POLYGON ((0 0, 1 0, 1 1, 0 1, 0 0))'
Note that shapely is clever enough to close the polygon on your behalf, i.e. you don't necessarily have to pass-in the first point again at the end.
请注意，shapely 足够聪明，可以代表您关闭多边形，即您不必在最后再次传入第一个点。
回答by dlask
The Polygonconstructor doesn't expect a list of Pointobjects but a list of point coordinates.
该Polygon构造并不期望列表Point对象，但点的坐标表。
See https://shapely.readthedocs.io/en/latest/manual.html#polygons
见https://shapely.readthedocs.io/en/latest/manual.html#polygons
回答by Malik Brahimi
回答by Adam
In version 1.7a2they have fixed this.
在版本中，1.7a2他们已修复此问题。
The code in question will just work.
有问题的代码将正常工作。
